Bunuel wrote:
A basketball team averaged z points per game for q games. If the team scored 100 points its next game, what was the team’s average in terms of z and q?
A \(\frac{z + 100}{q}\)
B \(\frac{zq + 100}{q + 1}\)
C \(\frac{zq + 100}{q}\)
D \(\frac{zq}{q + 1}\)
E \(\frac{z + 100}{q + 1}\)
IMO B
1 game z points
q game zq points
100 points in next game
\(\frac{zq + 100}{q + 1}\)
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Quote which i can relate to.
Many of life's failures happen with people who do not realize how close they were to success when they gave up.
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89% (00:53) correct 
