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# A bus B1 leaves place M at 6am and reaches place N at 10am.

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Intern
Joined: 02 Jan 2009
Posts: 3
Schools: ISB
A bus B1 leaves place M at 6am and reaches place N at 10am. [#permalink]

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04 Jan 2009, 20:32
A bus B1 leaves place M at 6am and reaches place N at 10am.
Another bus B2 leave place N at 2am and reaches M at 11:30 am.
At what time do they meet ??
8:55 am
9:26 am
9:00 am
11:30 am

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VP
Joined: 17 Jun 2008
Posts: 1479

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04 Jan 2009, 22:52
I am getting 7:38 a.m. and this is not there in the options.

My approach:
If x is the distance between M and N and if the two buses meet at t a.m., then

(t-6)*(x/4) + (t-2)*(x/13.5) = x
or, t = 7.63 or 7:38 a.m.
Intern
Joined: 02 Jan 2009
Posts: 3
Schools: ISB

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05 Jan 2009, 09:36
Hi,
In the eq:
(t-6)*(x/4) + (t-2)*(x/13.5) = x

Could u pls let me know from where 13.5 comes..Also if u can explain the logic that wud be of immense help !!!
Thx
SVP
Joined: 29 Aug 2007
Posts: 2427

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05 Jan 2009, 15:48
romrubiens wrote:
A bus B1 leaves place M at 6am and reaches place N at 10am. Another bus B2 leave place N at 2am and reaches M at 11:30 am. At what time do they meet ??

8:55 am
9:26 am
9:00 am
11:30 am

I too got 7:37777 am but needs more work.

Hold on............
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Intern
Joined: 01 Jan 2009
Posts: 7
Schools: UCB, UCLA

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05 Jan 2009, 22:32
Answer should be 103/13.5 = 7.62
SVP
Joined: 29 Aug 2007
Posts: 2427

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06 Jan 2009, 22:20
GMAT TIGER wrote:
romrubiens wrote:
A bus B1 leaves place M at 6am and reaches place N at 10am. Another bus B2 leave place N at 2am and reaches M at 11:30 am. At what time do they meet ??

8:55 am
9:26 am
9:00 am
11:30 am

I too got 7:37777 am but needs more work.

Hold on............

again its the same.
x(t-6)/4 + x(t-2)/9.5 = x
t = 7.63 i.e 7.38 am.

do you have OA/OE?
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Intern
Joined: 02 Jan 2009
Posts: 3
Schools: ISB

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06 Jan 2009, 22:52
No I dunn have an OA/OE... This q was from one of the quant apti books for GMAT.
I got the basic idea as how to solve questions of this type..
Thx..
Senior Manager
Joined: 02 Nov 2008
Posts: 254

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07 Jan 2009, 00:21
i'm quite certain the answer choices listed are not correct
Intern
Joined: 22 Nov 2006
Posts: 12

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09 Jan 2009, 06:37
let the distance be x.
so time speed of A = x/4
speed of B = x/9.5
relative speed between them = x/4 - x/9.5
time to meet = x/(x/4 - x/9.5) = (9.5*4).(9.5-4) =~ 7
Hence time when they meet = 2 am + 7 hrs = 9 am.

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This is not a quality discussion. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

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Re: Meeting time ???   [#permalink] 09 Jan 2009, 06:37
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# A bus B1 leaves place M at 6am and reaches place N at 10am.

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