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A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 02:26
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Re: A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 02:41
Let time for first trip be x hrs
For first trip distance travelled = 60x For round trip distance travelled 40(x+4) = 40x+160
60x = 40x + 160 x = 8 hrs.
Total Round trip distance = 60*8*2 = 960 kilometers



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Re: A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 04:44
Bunuel wrote: A bus traveled from its depot to its destination at an average speed of 60 kilometers per hour. On its return to the depot along the same route, the bus traveled at an average speed of only 40 kilometers per hour, making the trip 4 hours longer. What is the total distance of the round trip?
A. 360 kilometers B. 400 kilometers C. 600 kilometers D. 800 kilometers E. 960 kilometers
Kudos for a correct solution. The difference of speed (6040 = 20 Kmph) is causing the delay of 4 hours Distance = Speed x Time Case 1: Distance = 60 x T While driving from Depot to Destination Case 2: Distance = 40 x (T+4) While returning from Destination to Depot Since the Distance Travelled is same in both cases therefore 60 x T = 40 x (T+4) i.e. 20 T = 160 i.e. T = 8 Hours i.e. (One side) Distance = 60 x T = 60 x 8 = 480 Total Distance of the round trip = 480 x 2 = 960 Km Answer: Option E
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Re: A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 04:57
Let the distance be D km and T be time taken (in hours). Now, D/60 = T; D/40 = T+4 D/60  D/40 = 4 D(4060/2400) = 4 D(20/2400) = 4 D = 480 km So, total distance = 960 km. Ans (E).
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Re: A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 05:07
Think about the concepts. The distance for the 2 trips is the same. So if RT = D, then R 1T 1 = R 2T 2. You can now plug in the infromation: 60T = 40 (T + 4). Solving T = 8 If the time for the first half took 8 hours and the speed was 60km/hour 8 x 60 = 480. The total distance is then 480 + 480.
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Re: A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 05:27
Bunuel wrote: A bus traveled from its depot to its destination at an average speed of 60 kilometers per hour. On its return to the depot along the same route, the bus traveled at an average speed of only 40 kilometers per hour, making the trip 4 hours longer. What is the total distance of the round trip?
A. 360 kilometers B. 400 kilometers C. 600 kilometers D. 800 kilometers E. 960 kilometers
Kudos for a correct solution. ALTERNATE METHODSpeed reduces from 60 to 40 during return journey i.e. New Speed while return (40) = (2/3)*60 But Distance = Speed x Time But if Distance is multiplied with some factor (2/3 in this case) then Time should be multiplied with reciprocal of that factor (2/3 in this case) i.e. Distance = (2/3)Speed x (3/2)Timei.e. Time during return should be (3/2) of previous time i.e. If Old Time = T then, New Time during return = (3/2)T and (3/2)T  T = 4 Hoursi.e. T = 8 Hours i.e. (One side) Distance = 60x8 or 40x12 = 480 Both ways Distance = 480*2 = 960 Answer: Option E
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Re: A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 10:31
One way to think about this is that the Distance of the two trips is same. Thus, 40t + 4 hours = 60t. Further, since t will be the same on each side of the equation, you can subtract 40t from each side. That leaves you with 4 hours at 40kph, or 160 km = 20t, or t=8 hours. Finally, since the question asks for the distance of the roundtrip, you can find this by 60 x 8 x 2, or 960 km.
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Re: A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 19:56
Bunuel wrote: A bus traveled from its depot to its destination at an average speed of 60 kilometers per hour. On its return to the depot along the same route, the bus traveled at an average speed of only 40 kilometers per hour, making the trip 4 hours longer. What is the total distance of the round trip?
A. 360 kilometers B. 400 kilometers C. 600 kilometers D. 800 kilometers E. 960 kilometers
Kudos for a correct solution. Distance = Speed x Time Trip 1: D = 60(x) Trip 2: D = 40(x+40) In round trip problems, the distances are the same. 60x=40(x+40) 60x=40x+160 20x=160 x=8 D = 60(8) D=480 480(2) = 960 km round trip.
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Re: A bus traveled from its depot to its destination at an average speed
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15 Jul 2015, 21:52
Speed*time=distance Let time for trip one be x Trip1 d1= 60*x Trip2 d2= 40*(x+4) D1=D2 So x= 8 So d1= 480 d2= 480 Total distance =960 kms E



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Re: A bus traveled from its depot to its destination at an average speed
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17 Jul 2015, 02:29
Bunuel wrote: A bus traveled from its depot to its destination at an average speed of 60 kilometers per hour. On its return to the depot along the same route, the bus traveled at an average speed of only 40 kilometers per hour, making the trip 4 hours longer. What is the total distance of the round trip?
A. 360 kilometers B. 400 kilometers C. 600 kilometers D. 800 kilometers E. 960 kilometers
Kudos for a correct solution. Time for bus to travel its route at average speed of 60kph: t Given the information, we have equation: \(60t=40(t+4)\) > \(t=8\)(hrs) > total distance of the round trip \(=60*8*2=960\)(km) Answer E



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Re: A bus traveled from its depot to its destination at an average speed
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17 Jul 2015, 10:39
Bunuel wrote: A bus traveled from its depot to its destination at an average speed of 60 kilometers per hour. On its return to the depot along the same route, the bus traveled at an average speed of only 40 kilometers per hour, making the trip 4 hours longer. What is the total distance of the round trip?
A. 360 kilometers B. 400 kilometers C. 600 kilometers D. 800 kilometers E. 960 kilometers
Kudos for a correct solution. Let one way distance=d Now, d/60+4=d/40 d/40d/60=4 3d2d/120=4 d=480 2d=960 km Answer E



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Re: A bus traveled from its depot to its destination at an average speed
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17 Jul 2015, 15:38
Bunuel wrote: A bus traveled from its depot to its destination at an average speed of 60 kilometers per hour. On its return to the depot along the same route, the bus traveled at an average speed of only 40 kilometers per hour, making the trip 4 hours longer. What is the total distance of the round trip?
A. 360 kilometers B. 400 kilometers C. 600 kilometers D. 800 kilometers E. 960 kilometers
Kudos for a correct solution. Two ways to solve this qn: (Maybe many ways) 1. Distance traveled is same in to and fro problems 60 * t = 40 * (t + 4) => Solving for t, t = 8 Distance = 8*60 = 480 (Usually this will be the trap answer). But they have asked for round trip distance. hence 2*D = 960. Option E 2. Time Difference btw the two trips is 4 hours. This difference is bec of difference in speed. Hence, T2  T1 =4 D/40  D/60 = 4 Solving for D, D=> 480; 2D => 960. Option E Would like to know if there are any standard techniques that can be applied to all Time/Distance/Speed problems. Thanks



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Re: A bus traveled from its depot to its destination at an average speed
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19 Jul 2015, 12:04
Bunuel wrote: A bus traveled from its depot to its destination at an average speed of 60 kilometers per hour. On its return to the depot along the same route, the bus traveled at an average speed of only 40 kilometers per hour, making the trip 4 hours longer. What is the total distance of the round trip?
A. 360 kilometers B. 400 kilometers C. 600 kilometers D. 800 kilometers E. 960 kilometers
Kudos for a correct solution. 800score Official Solution:The distance formula is Distance = Rate × Time. To solve this question, set x as the length of time (in hours) for the first trip. The distance to the destination city is 60 × x, where rate = 60 and time = x. The return trip was 4 hours longer, so its distance is 40(x + 4). Since we know the distances are the same, we can set them equal to each other and solve for x: 60x = 40(x + 4) 60x = 40x + 160 20x = 160 x = 8. So, the trip took 8 hours, and its distance is 8 × 60 = 480 kilometers. The question asks for the roundtrip distance, so we double the length of the oneway trip: 480 × 2 = 960 kilometers. The correct answer is choice (E).
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Re: A bus traveled from its depot to its destination at an average speed
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