Bunuel
A can build an entire wall in 50 days whereas B, who is a demolition man, can break the entire wall in 60 days. If they work on alternate days with A starting, in how many days will the wall be built completely for the first time?
A. 299
B. 300
C. 589
D. 599
E. 600
A's 1 day work is 1/50 and B's 1 day work is 1/60. So, A and B's 1-day work is 1/50-1/60=1/300 i.e. total work to do is 300 units.
A can finish building 300/50=6 units a day whereas B can break 300/60=5 units a day.
Therefore, in 2 days, effective work done by A and B is 6-5=1 units only. Let they take x/2 days (since in 2 days, 1 unit is done)
Also, the wall is built for the first time when A is finishing because if B finishes, they will break it keeping the wall unfinished.
(x/2)*1 + 6 = 300 or, x=588. Here, I am adding 6 to make sure that the last work is done by A.
Therefore, the number of days is 588+1=589. I have added 1 because the last work was done by A after they paired up on alternate days for 588 days. Option (C) is correct.