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# A car traveled 75 percent of the distance from town A to town B by tra

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Joined: 02 Sep 2009
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Kudos [?]: 135380 [0], given: 12691

A car traveled 75 percent of the distance from town A to town B by tra [#permalink]

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02 Nov 2017, 22:24
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Question Stats:

68% (01:43) correct 32% (02:04) wrong based on 65 sessions

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A car traveled 75 percent of the distance from town A to town B by traveling for T hours at an average speed of V miles per hour. The car traveled at an average speed of S miles per hour for the remaining part of the trip. Which of the following expressions represents the time the car traveled at S miles per hour?

(A) VT/S
(B) VS/(4T)
(C) 4VT/(3S)
(D) 3S/(VT)
(E) VT/(3S)
[Reveal] Spoiler: OA

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Kudos [?]: 135380 [0], given: 12691

Director
Joined: 18 Aug 2016
Posts: 597

Kudos [?]: 179 [1], given: 136

GMAT 1: 630 Q47 V29
Re: A car traveled 75 percent of the distance from town A to town B by tra [#permalink]

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02 Nov 2017, 22:38
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Bunuel wrote:
A car traveled 75 percent of the distance from town A to town B by traveling for T hours at an average speed of V miles per hour. The car traveled at an average speed of S miles per hour for the remaining part of the trip. Which of the following expressions represents the time the car traveled at S miles per hour?

(A) VT/S
(B) VS/(4T)
(C) 4VT/(3S)
(D) 3S/(VT)
(E) VT/(3S)

Case 1: S = V miles/Hr; T = T hrs; D = VT
Case 2: S = S miles/Hr; T = x hrs; D = xS

VT:xS::3:1
x = VT/3S

E
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Kudos [?]: 179 [1], given: 136

Manager
Joined: 05 Dec 2016
Posts: 248

Kudos [?]: 26 [0], given: 49

Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
Re: A car traveled 75 percent of the distance from town A to town B by tra [#permalink]

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03 Nov 2017, 02:01
RTD chart, let x be the distance and y time to cover the remaining distance with V speed:
R T D
Vm/h Th. 0,75x
Sm/h yh. 0,25x

To make the correct equation we should to find x in terms of (VT) and in terms of (Sy)
0,75x=VT ==> x=VT/0,75
0,25x=Sy ==> x=Sy/0,25

VT/0,75=Sy/0,25
solving
y=VT/3S

Kudos [?]: 26 [0], given: 49

VP
Joined: 22 May 2016
Posts: 1113

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A car traveled 75 percent of the distance from town A to town B by tra [#permalink]

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04 Nov 2017, 15:17
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Bunuel wrote:
A car traveled 75 percent of the distance from town A to town B by traveling for T hours at an average speed of V miles per hour. The car traveled at an average speed of S miles per hour for the remaining part of the trip. Which of the following expressions represents the time the car traveled at S miles per hour?

(A) VT/S
(B) VS/(4T)
(C) 4VT/(3S)
(D) 3S/(VT)
(E) VT/(3S)

Choose smart numbers.
For $$\frac{3}{4}$$, I kept the ratio but increased the values slightly to $$\frac{6}{8}$$
Let distance for leg 1 = 6
Let distance for leg 2 = 2

Let V = leg 1 speed = 3 mph, hence
T = leg 1 time = $$\frac{6}{3}=$$ 2 hrs
Let S = leg 2 speed = 1, hence
?? = leg 2 time = $$\frac{2}{1}=$$ 2 hrs

With T = 2, V = 3, S = 1, find the answer choice that yields 2

(A) VT/S: 6/1 = 6. No match

(B) VS/(4T): 3/2. No match

(C) 4VT/(3S):24/3 = 8. No match.

(D) 3S/(VT): 3/6 = 1/2. No match.

(E) VT/(3S): 6/3 = 2. MATCH

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Target Test Prep Representative
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Re: A car traveled 75 percent of the distance from town A to town B by tra [#permalink]

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06 Nov 2017, 16:37
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Bunuel wrote:
A car traveled 75 percent of the distance from town A to town B by traveling for T hours at an average speed of V miles per hour. The car traveled at an average speed of S miles per hour for the remaining part of the trip. Which of the following expressions represents the time the car traveled at S miles per hour?

(A) VT/S
(B) VS/(4T)
(C) 4VT/(3S)
(D) 3S/(VT)
(E) VT/(3S)

If we let d = the total distance, then during the first part of the trip, we have:

VT = 0.75d

VT/0.75 = d

VT/(3/4) = d

4VT/3 = d

So, the remaining distance is:

0.25(4VT/3) = VT/3

Since the car traveled at S miles per hour, the time was (VT/3)/S = VT/(3S).

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Re: A car traveled 75 percent of the distance from town A to town B by tra   [#permalink] 06 Nov 2017, 16:37
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