gaurav5691 wrote:
CrackVerbalGMATFrom statement II alone, 2S + T = 3.40
By hit and trial can we not find out the solution, which is S=1, T=1.4
Second value being S=2, T=-0.6.
Since T cant be negative, hence we reject the other value.
We also arent able to determine any other possible positive value for this equation.
We explicitly did not require the usage of Statement 1
Hence B should be the answer
Hello Gaurav 5691,
Using the same technique of Hit & Trial, why is not possible that S = 1.5 and T = 0.4?
Why are 1 and 1.4 so special?
The term 'Hit & Trial' is usually used with a negative connotation by most test takers I have interacted with (almost with a condescending tone). Trial & Error (or what is called Hit & Trial) is a very important method for deriving empirical results and should be employed while solving questions in standardized tests.
However, employing it recklessly like you are doing here is not a good idea. There is absolutely no premise to your argument, where in you say that there are only two sets of values that will satisfy a Linear equation in two variables.
The equation 2S + T = 3.40 can be satisfied by infinite combinations of S and T.
A very basic concept in Algebra – if you have 2 unknowns, you need 2 independent equations to solve for unique values of both unknowns.
That’s why the equation given in statement 2 needs to be combined with statement 1 to get a unique answer.
The correct answer is C.
Hope that helps!
_________________