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A certain bridge is 4,024 feet long. Approximately how many minutes...
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26 May 2016, 21:34
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78% (02:19) correct 22% (02:24) wrong based on 1105 sessions
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A certain bridge is 4,024 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 20 miles per hour? (1 mile = 5,280 feet)
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20 Mar 2017, 21:25
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Hi amandakay,
The GMAT would never expect you to calculate the exact value of 4024/5280, so if you're ever thinking about doing something so "calculation heavy", then there's almost certainly a faster or easier way to get to the correct answer. In this prompt, you should notice the word "approximately" - that means that you DON'T have to calculate that fraction, but you do have to estimate the value.
If we 'round down', then 4024 ft./5280 ft. is a little less than 4/5 of a mile. Knowing THAT, and that 20 mph is 1 mile every 3 minutes, can you correctly answer the question?
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19 Mar 2017, 12:01
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Here's another method that allowed me to solve the question in approximately 30 seconds:
20 miles per hour translates to traveling 1 mile every 3 minutes. Since the bridge is longer than 1/2 mile but shorter than 1 mile, the answer must be between 1.5 and 3 minutes. The only answer choice that fits this range is 2 minutes.
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14 Jun 2016, 12:34
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nalinnair wrote:
A certain bridge is 4,024 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 20 miles per hour? (1 mile = 5,280 feet)
(A) 1 (B) 2 (C) 4 (D) 6 (E) 7
First, convert the speed to feet per minute.
20 miles per hour = ( 20 * 5280 ) feet per 60 minutes.
We can eliminate (A) because \(\frac{4024}{5280}\) is not equal to \(\frac{1}{3}\). The only answer choice remaining is (B). Therefore, (B) is the answer.
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19 Mar 2017, 12:32
Does anyone have a tip for a quick way to solve the division of 4024/5280? This is where I spend the majority of my time on the problem and am wondering if I can do something faster. I do a lot of trial and error.
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20 Mar 2017, 01:56
nalinnair wrote:
A certain bridge is 4,024 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 20 miles per hour? (1 mile = 5,280 feet)
(A) 1 (B) 2 (C) 4 (D) 6 (E) 7
distance = 4024 ft = 4024/5280 miles
time taken = 4024/5280*20 hours= 0.76 hours = 2.28 minutes close to 2 minutes
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07 Apr 2018, 03:52
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nalinnair wrote:
A certain bridge is 4,024 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 20 miles per hour? (1 mile = 5,280 feet)
(A) 1 (B) 2 (C) 4 (D) 6 (E) 7
hello friends
here is a quick way to solve it
if 20 miles = 60 min---> then 1 mile = 3 min
if length of bridge (4,024 feet) is shorter than 1 mile (5,280 feet)
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19 Aug 2018, 21:54
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Convert the rate from miles per hour to feet per minute. 20 miles per hour = 20*5280/60 = 1760 Now devide distance by rate to find time Time = 4024/1760 =~2 Answer B
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Re: A certain bridge is 4,024 feet long. Approximately how many minutes...
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23 Aug 2018, 16:41
nalinnair wrote:
A certain bridge is 4,024 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 20 miles per hour? (1 mile = 5,280 feet)
(A) 1 (B) 2 (C) 4 (D) 6 (E) 7
The length of the bridge, in miles, is:
4,024/5,280 = 503/660, which is about 500/660 = 50/66 = 25/33.
Using the formula: time = distance/rate, we see that the time, in hours, is:
[25/33]/20 = 25/(33 x 20) hours
So the time in minutes is:
25/(33 x 20) x 60 = (25 x 3)/33 = 25/11, which is about 2 minutes.
A certain bridge is 4,024 feet long. Approximately how many minutes...
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13 Oct 2018, 11:57
nalinnair wrote:
A certain bridge is 4,024 feet long. Approximately how many minutes does it take to cross this bridge at a constant speed of 20 miles per hour? (1 mile = 5,280 feet)
(A) 1 (B) 2 (C) 4 (D) 6 (E) 7
I used a combination of algebra and backsolve to tackle this problem in <1min:
Figure out the rate in ft / min: \(\frac{20 mi}{hour}*\frac{*1 hr}{60 min}*\frac{1 mi}{5280 ft} = \frac{5280 ft}{3 min}\)
By examination, (B) is the only that makes the most sense. In other words, 4,024 is about 2/3 of 5,280.
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