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# A certain college has a student-to-teacher ratio of 11 to 1.

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Manager
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A certain college has a student-to-teacher ratio of 11 to 1.  [#permalink]

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Updated on: 12 Sep 2013, 07:52
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87% (01:46) correct 13% (02:08) wrong based on 201 sessions

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A certain college has a student-to-teacher ratio of 11 to 1. The average (arithmetic mean) annual salary for teachers is $26,000. If the college pays a total of$3,380,000 in annual salaries to its teachers, how many students does the college have ?

(A) 130
(B) 169
(C) 1,300
(D) 1,430
(E) 1,560

Hi, this is a pretty easy question, I know. Still, It took me a bit more than 3 min to perform all the calculation.. Are there any tips on how to calculate everything quicker? In general, I will greatly appreciate if anyone can share any ideas on how to do calculations quickly.. Calculations of fractions-decimals or just large numbers take my time. moreover I just tend to make careless mistakes here being pressed on time.......Please, advise..

Thanks much

Originally posted by chica on 27 Jan 2008, 10:39.
Last edited by Bunuel on 12 Sep 2013, 07:52, edited 1 time in total.
Edited the question and added the OA.
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27 Jan 2008, 10:52
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I don't know faster way than this one:
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27 Jan 2008, 16:07
i agree, i cant see a 'fast' way.

first step is to figure out how many total teachers there are, which is possible as you know the average salary and total salary

average = sum/total --> 26,000 = 3,380,000 / total --> total =130

students/teachers = 11/1 --> 11/1 = x/130 where x=# of students --> x=130*11
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27 Jan 2008, 16:45
Agree.. Just need to sharpen your basic math skills. Dividing 3380000/26000 should actually calculate out pretty fast when you cancel out some zeros.
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27 Jan 2008, 16:56
I agree as well. Just gunna have to do some calculations.

3380000/26000 --> 130 then just 130*11 =1430.
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27 Jan 2008, 19:58
chica wrote:
A certain college has a student-to-teacher ratio of 11 to 1. The average (arithmetic mean) annual salary for teachers is $26,000. If the college pays a total of$3,380,000 in annual salaries to its teachers, how many students does the college have ?
(A) 130
(B) 169
(C) 1,300
(D) 1,430
(E) 1,560

Hi, this is a pretty easy question, I know. Still, It took me a bit more than 3 min to perform all the calculation.. Are there any tips on how to calculate everything quicker? In general, I will greatly appreciate if anyone can share any ideas on how to do calculations quickly.. Calculations of fractions-decimals or just large numbers take my time. moreover I just tend to make careless mistakes here being pressed on time.......Please, advise..

Thanks much

no . of student = (11) ($3,380,000 /$26,000) = 11 (3380 / 26) = 11 (1649 / 13) = 11 (130) = 1,430

reducing numerator and denomenator would be sometime easy.
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12 Sep 2013, 05:47
Could someone show me a purely algebraic approach. I can't connect those elements (two equations). I solve fast via the common sense, but I it looks like I am doing something silly on the proportions side.

I have this ready, after taking out three 0's, $$26t = 3800$$ (after 3800/t=26), and then since we have $$11t=s$$ it must be that $$\frac{s}{11}=\frac{t}{1}$$? But then, if it is true, I am confused with my common sense...please help me untangle myself. How do you express ratios as stated in the problem?
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12 Sep 2013, 06:19
obs23 wrote:
Could someone show me a purely algebraic approach. I can't connect those elements (two equations). I solve fast via the common sense, but I it looks like I am doing something silly on the proportions side.

I have this ready, after taking out three 0's, $$26t = 3800$$ (after 3800/t=26), and then since we have $$11t=s$$ it must be that $$\frac{s}{11}=\frac{t}{1}$$? But then, if it is true, I am confused with my common sense...please help me untangle myself. How do you express ratios as stated in the problem?

chica,

This calculation is v easy if you know 13^2 = 169.

3380000/ 26000 = 3380/26 = 1690/13 = 130
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12 Sep 2013, 06:53
Quote:
chica,

This calculation is v easy if you know 13^2 = 169.

3380000/ 26000 = 3380/26 = 1690/13 = 130

Dude, I appreciate your effort, but I am not looking for a solution, I am looking for a specific way to solve, the one I need to get a grasp of.

Thanks.
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12 Sep 2013, 07:33
obs23 wrote:
Could someone show me a purely algebraic approach. I can't connect those elements (two equations). I solve fast via the common sense, but I it looks like I am doing something silly on the proportions side.

I have this ready, after taking out three 0's, $$26t = 3800$$ (after 3800/t=26), and then since we have $$11t=s$$ it must be that $$\frac{s}{11}=\frac{t}{1}$$? But then, if it is true, I am confused with my common sense...please help me untangle myself. How do you express ratios as stated in the problem?

This is an arithmetic question, using algebra and adding variables only makes this problem complicated. Additionally, you shouldn't be concerned about expressing the solution in ratios if that doesn't appear as an answer form. But regarding your equation. Your math is correct s/11 = t/1 (This is confirmed through backsolving with the arithmetic... 1430/11 = 130/1) But this proportion doesn't actually give you the answer to the problem since there are two unsolved variables, so I'm not sure what use it is.
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12 Sep 2013, 07:39
2
obs23 wrote:
Could someone show me a purely algebraic approach. I can't connect those elements (two equations). I solve fast via the common sense, but I it looks like I am doing something silly on the proportions side.

I have this ready, after taking out three 0's, $$26t = 3800$$ (after 3800/t=26), and then since we have $$11t=s$$ it must be that $$\frac{s}{11}=\frac{t}{1}$$? But then, if it is true, I am confused with my common sense...please help me untangle myself. How do you express ratios as stated in the problem?

Hi obs, if you're intent on solving the question through ratios, then you can, but it's not necessarily the best approach. That being said, let's attack it as a ratio problem.

Firstly, there's a slight typo in how you copied the math, it's actually $$26t = 3,380$$. You can then figure out that whatever t is, if you multiply it by 11 you'll get the number of students. So yes $$\frac{s}{11}=\frac{t}{1}$$, and you already have $$26t = 3,380$$ so $$t= \frac{3,380}{26}$$. Now solve t for 130, and then $$11t=s$$. s is 1430.

A sneakier way to solve this:

The GMAT will always try and trap you, so if it asks for the number of students (s), the number of teachers (t) will also be a trap answer somewhere on the list. If you recognize this, then all you have to do is look for the two answer choices that are 11 away from one another. The bigger one will be the answer and the smaller will be the trap. This kind of "fourth wall" shortcut isn't for everyone, but it can be very helpful when crunched for time or unsure about the math.

Hope this helps!
-Ron
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14 Sep 2013, 02:19
VeritasPrepRon wrote:
obs23 wrote:
Could someone show me a purely algebraic approach. I can't connect those elements (two equations). I solve fast via the common sense, but I it looks like I am doing something silly on the proportions side.

I have this ready, after taking out three 0's, $$26t = 3800$$ (after 3800/t=26), and then since we have $$11t=s$$ it must be that $$\frac{s}{11}=\frac{t}{1}$$? But then, if it is true, I am confused with my common sense...please help me untangle myself. How do you express ratios as stated in the problem?

Hi obs, if you're intent on solving the question through ratios, then you can, but it's not necessarily the best approach. That being said, let's attack it as a ratio problem.

Firstly, there's a slight typo in how you copied the math, it's actually $$26t = 3,380$$. You can then figure out that whatever t is, if you multiply it by 11 you'll get the number of students. So yes $$\frac{s}{11}=\frac{t}{1}$$, and you already have $$26t = 3,380$$ so $$t= \frac{3,380}{26}$$. Now solve t for 130, and then $$11t=s$$. s is 1430.

A sneakier way to solve this:

The GMAT will always try and trap you, so if it asks for the number of students (s), the number of teachers (t) will also be a trap answer somewhere on the list. If you recognize this, then all you have to do is look for the two answer choices that are 11 away from one another. The bigger one will be the answer and the smaller will be the trap. This kind of "fourth wall" shortcut isn't for everyone, but it can be very helpful when crunched for time or unsure about the math.

Hope this helps!
-Ron

Thanks Ron, all makes sense. As for the use, I was just a bit rusty on ratios so I wanted to make sure I do the simple stuff correctly in algebraic terms.
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Re: A certain college has a student-to-teacher ratio of 11 to 1.  [#permalink]

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14 Sep 2013, 07:58
No problem obs23, as mentioned it may not be the most obvious way to solve this problem, but I like to remind students that pretty much any GMAT math problem can be solved in a variety of ways. If you have one way to solve the problem, you're probably okay, but if you have three different ways, then you're definitely in great shape to solve any variation of the problem on test day. Hope this makes sense!

-Ron
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Re: A certain college has a student-to-teacher ratio of 11 to 1.  [#permalink]

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27 Oct 2018, 11:37
Easy

13^2 = 169.

3380000/ 26000 = 3380/26 = 1690/13 = 130

Re: A certain college has a student-to-teacher ratio of 11 to 1.   [#permalink] 27 Oct 2018, 11:37
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