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17 Jul 2023, 01:51
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B
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Difficulty:
65%
(hard)
Question Stats:
58% (01:55) correct
42%
(01:46)
wrong
based on 153
sessions
History
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A certain computer has five identical ports to plug in accessories. If a user has two different accessories, and there is only one correct port to plug each accessory into, how many INCORRECT ways are there to plug in the accessories? (The correct way is when both accessories are plugged into their respective ports.)
A. 16
B. 19
C. 20
D. 21
E. 25
A. 16
B. 19
C. 20
D. 21
E. 25
20 Jul 2023, 01:46
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There is clearly a single way of doing the correct way: when both the accessories are connected to correct port.
Total number of ways of connecting can be done by slot method : 5x4 = 20
( First accessory can be connected to any 5 ports
Second accessory can be connected to any remaining 4 ports.)
Hence, Incorrect way to plug in the accessories = total - correct way = 20-1 = 19.
Answer = B
Posted from my mobile device
Total number of ways of connecting can be done by slot method : 5x4 = 20
( First accessory can be connected to any 5 ports
Second accessory can be connected to any remaining 4 ports.)
Hence, Incorrect way to plug in the accessories = total - correct way = 20-1 = 19.
Answer = B
Posted from my mobile device
31 Oct 2023, 23:44
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I got this one wrong. I didn't do 5*4*1 which makes sense.
I did this...please correct my logic.
A and B represent the two different plugs.
4*4=16 (4 ways incorrect for each of the plugs)
+3 (If B is plugged correctly, then A has 3 options incorrect.)
+3 (If A is plugged correctly, then B has 3 options incorrect.)
16+3+3 = 22 ways... T^T
I did this...please correct my logic.
A and B represent the two different plugs.
4*4=16 (4 ways incorrect for each of the plugs)
+3 (If B is plugged correctly, then A has 3 options incorrect.)
+3 (If A is plugged correctly, then B has 3 options incorrect.)
16+3+3 = 22 ways... T^T
