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30 Apr 2024, 11:14
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I think this is the simplest way to do it:
aboobna
Joined: 20 Jan 2024
Last visit: 04 Apr 2026
Posts: 8
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Given Kudos: 19
Location: India
Schools: ISB '26 (WL)
GMAT Focus 1: 675 Q86 V82 DI82 
GPA: 8.23
15 Jun 2025, 04:50
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Have a quite odd way Chocolate Distribution System: Here lets assume 64 (Classes) are number of chocolates being distributed, and it is told that we have 37 Teachers, Each teachers will be given 1 chocolate since mentioned, at least one class, Now there are 64-37= 27 chocolate to be remaining. To Minimize the number of 3 chocolates (Classes) we will distribute one each to everyone, again that way each would have 2 chocolates, But since there are only 27 chocolates it got exhausted in between due to which we don't have to give 3rd chocolate to anyone. Therefore least 0 can be given.
Now, to maximize i will try to give more chocolates since we have already given 1 , it would be three chocolates since we have 27 chocolates left we will give 26/2 = 13 teachers . Therefore maximum would be 13.
Now, to maximize i will try to give more chocolates since we have already given 1 , it would be three chocolates since we have 27 chocolates left we will give 26/2 = 13 teachers . Therefore maximum would be 13.
Fisayofalana
25 Dec 2025, 19:09
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I treated like an overlapping sets question and min/max what was in question. I set this up anytime there is an overlapping set question with 3 groups.
Bunuel
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