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03 Nov 2011, 14:19
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (02:05) correct
26%
(02:00)
wrong
based on 936
sessions
History
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Time
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Not Attempted Yet
A certain football team played x games last season, of which the team won exactly y games. If tied games were not possible, how many games did the team win last season?
(1) If the team had lost two more of its games last season, it would have won 20 percent of its games for the season.
(2) If the team had won three more of its games last season, it would have lost 30 percent of its games for the season.
(1) If the team had lost two more of its games last season, it would have won 20 percent of its games for the season.
(2) If the team had won three more of its games last season, it would have lost 30 percent of its games for the season.
As I don't have an official answer, I will go for C. This is how I did this. Can you guys please help and let me know whether I am correct or not?
Games Lost = x-y
Considering statement 1 --> x-y+2= 0.20x
Considering statement 2 --> y+3=0.3(x-y)
Two variables and two equations and we can solve for y.
Games Lost = x-y
Considering statement 1 --> x-y+2= 0.20x
Considering statement 2 --> y+3=0.3(x-y)
Two variables and two equations and we can solve for y.
enigma123
Let me add a little tip about this conclusion. Make sure that the equations you have are distinct. You can solve for y only if you have two equations. If both the equations are the same (even though they may not appear to be same), you cannot solve for y.
General Discussion
03 Nov 2011, 22:02
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Your approach is correct, though the equations you are getting are incorrect.
Using statement 1: y-2 = 0.20x [i.e. equate the number of games won to 20% of the total games]
Using statement 2: x-y-3 = 0.30x [i.e. equate the number of games lost to 30% of the total games]
The answer should still be (C).
Using statement 1: y-2 = 0.20x [i.e. equate the number of games won to 20% of the total games]
Using statement 2: x-y-3 = 0.30x [i.e. equate the number of games lost to 30% of the total games]
The answer should still be (C).
