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# A certain kennel will house 24 dogs for 7 days. Each dog requires 10

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IIMA, IIMC School Moderator
Joined: 04 Sep 2016
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A certain kennel will house 24 dogs for 7 days. Each dog requires 10  [#permalink]

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23 May 2018, 06:26
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94% (01:30) correct 6% (01:39) wrong based on 70 sessions

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A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day. If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food, how many cases will the kennel need to feed all of the dogs for 7 days?

A. 5
B. 6
C. 7
D. 8
E. 9

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Re: A certain kennel will house 24 dogs for 7 days. Each dog requires 10  [#permalink]

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23 May 2018, 06:51
1
A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day. If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food, how many cases will the kennel need to feed all of the dogs for 7 days?

A. 5

B. 6

C. 7

D. 8

E. 9

Solve the question by breaking it into parts
Quote:
A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day.

Total food requirement = 24*7*10 dog days ounce
Quote:
If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food

Total purchase of 30 cans = 240 ounces

So, Number of cases required for feeding the dogs for 7 days is $$\frac{24*7*10}{30*8}$$ = 7 cases, Answer must be (C)
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Re: A certain kennel will house 24 dogs for 7 days. Each dog requires 10  [#permalink]

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08 Feb 2020, 12:21
1
A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day. If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food, how many cases will the kennel need to feed all of the dogs for 7 days?

A. 5
B. 6
C. 7
D. 8
E. 9

Since each dog requires 10 ounces of dog food per day, 24 dogs require 10 x 24 = 240 ounces of dog food per day and 240 x 7 = 1680 ounces of dog food for the 7 days.

Since each case of dog food has 30 cans and each can has 8 ounces of dog food, a case has 30 x 8 = 240 ounces of dog food.

Therefore, 1680/240 = 7 cases of dog food are needed to feed 24 dogs for 7 days.

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Re: A certain kennel will house 24 dogs for 7 days. Each dog requires 10  [#permalink]

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09 Feb 2020, 05:14
A certain kennel will house 24 dogs for 7 days. Each dog requires 10 ounces of dog food per day. If the kennel purchases dog food in cases of 30 cans each and if each can holds 8 ounces of dog food, how many cases will the kennel need to feed all of the dogs for 7 days?

A. 5
B. 6
C. 7
D. 8
E. 9

Since each dog requires 10 ounces of dog food per day, 24 dogs require 10 x 24 = 240 ounces of dog food per day and 240 x 7 = 1680 ounces of dog food for the 7 days.

Since each case of dog food has 30 cans and each can has 8 ounces of dog food, a case has 30 x 8 = 240 ounces of dog food.

Therefore, 1680/240 = 7 cases of dog food are needed to feed 24 dogs for 7 days.

_________________

# Scott Woodbury-Stewart

Founder and CEO

Scott@TargetTestPrep.com
202 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Re: A certain kennel will house 24 dogs for 7 days. Each dog requires 10   [#permalink] 09 Feb 2020, 05:14
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