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Updated on: 01 Sep 2019, 13:33
Originally posted by adarsh12345 on 12 Nov 2009, 08:59.
Last edited by MikeScarn on 01 Sep 2019, 13:33, edited 2 times in total.
Last edited by MikeScarn on 01 Sep 2019, 13:33, edited 2 times in total.
Edited the question.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
56% (01:35) correct
44%
(01:43)
wrong
based on 2325
sessions
History
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Time
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Not Attempted Yet
A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the seminar attended at least one of the two sessions, how many of the people attended the morning session only.
(1) 3/4 of the people attended both sessions
(2) 7/8 of the people attended the afternoon session
(1) 3/4 of the people attended both sessions
(2) 7/8 of the people attended the afternoon session
12 Nov 2009, 09:22
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A certain one-day seminar consisted of a morning session and an afternoon session. If each of the 128 people attending the seminar attended at least one of the two sessions, how many of the people attended the morning session only.
(1) 3/4 of the people attended both sessions
(2) 7/8 of the people attended the after noon session
(1) 3/4 of 128 is 96. So we know that 96 people attended both seminars. If you draw Venn diagram you'll see that 96 is the intersection of the people who attended morning session and the evening session. This only tells that minimum # of people for the morning session is 96. Morning only could be from 0 to 32. Not sufficient.
(2) 7/8 of the people attended the after noon session=112 people. This directly tells that 112 attended after noon session, as each of the 128 people attending the seminar attended at least one of the two sessions hence rest of the people 16, must have been attending the morning session and not attending the evening, which IS only morning session attendant #.
Again on Venn diagram 112 would be: only afternoon + intersection of morning and afternoon, so the third part which is morning only would be: total-(Afternoon and intersection)=128-112=16.
Answer: B.
P.S. You can attach the file directly to the question, so that everyone see it on the page.
(1) 3/4 of the people attended both sessions
(2) 7/8 of the people attended the after noon session
(1) 3/4 of 128 is 96. So we know that 96 people attended both seminars. If you draw Venn diagram you'll see that 96 is the intersection of the people who attended morning session and the evening session. This only tells that minimum # of people for the morning session is 96. Morning only could be from 0 to 32. Not sufficient.
(2) 7/8 of the people attended the after noon session=112 people. This directly tells that 112 attended after noon session, as each of the 128 people attending the seminar attended at least one of the two sessions hence rest of the people 16, must have been attending the morning session and not attending the evening, which IS only morning session attendant #.
Again on Venn diagram 112 would be: only afternoon + intersection of morning and afternoon, so the third part which is morning only would be: total-(Afternoon and intersection)=128-112=16.
Answer: B.
P.S. You can attach the file directly to the question, so that everyone see it on the page.
16 Aug 2011, 12:24
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Warlock007
Dear Fluke
were "only" not there
then B would have been a straight away answer (why would we need St A)
were "only" not there
then B would have been a straight away answer (why would we need St A)
Actually, just the reverse would be correct. Please see the attached picture.
Attachment:
Seminar_Morning_Afternoon.JPG [ 9.91 KiB | Viewed 91203 times ]
Morning Session Only = Grey Color = M
Both (Morning Session+Afternoon) = Orange Color = M&A
Afternoon Session Only = Yellow Color = A
Q: If M+M&A+A=128
M=?
St1:
M&A=96
Not Sufficient.
St2:
M&A+A=112
Now, we know M&A+A+M=128
M&A+A=112
So, M=16(Morning Session only)
Sufficient.
Ans: "B"
******************************************************************************
Now, if the question were: How many people attended morning session, we are asked to find M+M&A
St1:
M&A=96
Not Sufficient.
St2:
M&A+A=112
Now, we can't find "M&A+M" using this information and the stem.
Not Sufficient.
Together:
We can find "A" and eventually "M&A+M".
Sufficient.
Ans: "C"
