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# A certain rectangular box A, has height of x units, length of y units

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Re: A certain rectangular box A, has height of x units, length of y units [#permalink]
Bunuel wrote:

Fresh GMAT Club Tests' Question:

A certain rectangular box A, has height of x units, length of y units and width of z units, where x, y, and z are positive integers. A second rectangular box B, has each of its dimensions - height, length and width, 50 percent smaller than that of rectangular box A. If the surface ares of rectangular box B is 2.5 unit^2, what is the volume of rectangular box A?

A. 1/4 unit^3
B. 1 unit^3
C. 2 unit^3
D. 4 unit^3
E. 10 unit^3

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Re: A certain rectangular box A, has height of x units, length of y units [#permalink]
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Bunuel wrote:

Fresh GMAT Club Tests' Question:

A certain rectangular box A, has height of x units, length of y units and width of z units, where x, y, and z are positive integers. A second rectangular box B, has each of its dimensions - height, length and width, 50 percent smaller than that of rectangular box A. If the surface ares of rectangular box B is 2.5 unit^2, what is the volume of rectangular box A?

A. 1/4 unit^3
B. 1 unit^3
C. 2 unit^3
D. 4 unit^3
E. 10 unit^3

sides of box b = x/2,y/2 and z/2

TSA = 2/4(xy+xz+zy)=2.5
or say (xy+xz+zy)= 5

since given that x,y,z are integers
so x=2,y=z=1
so volume would be 2*1*1= 2 IMO c

Originally posted by Archit3110 on 24 Dec 2018, 07:01.
Last edited by Archit3110 on 25 Dec 2018, 01:42, edited 1 time in total.
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Re: A certain rectangular box A, has height of x units, length of y units [#permalink]
You got the whole solution correct except for the last step which would be 2*1*1 = 2 unit^2

Hence Option (C) is correct.

Best,
Archit3110 wrote:
sides of box b = x/2,y/2 and z/2

TSA = 2/4(xy+xz+zy)=2.5
or say (xy+xz+zy)= 5

since given that x,y,z are integers
so x=2,y=z=1
so volume would be 2*2*1= 4 IMO D
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Re: A certain rectangular box A, has height of x units, length of y units [#permalink]
wish you merry xmas..

You got the whole solution correct except for the last step which would be 2*1*1 = 2 unit^2

Hence Option (C) is correct.

Best,
Archit3110 wrote:
sides of box b = x/2,y/2 and z/2

TSA = 2/4(xy+xz+zy)=2.5
or say (xy+xz+zy)= 5

since given that x,y,z are integers
so x=2,y=z=1
so volume would be 2*2*1= 4 IMO D
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Re: A certain rectangular box A, has height of x units, length of y units [#permalink]
Bunuel wrote:

Fresh GMAT Club Tests' Question:

A certain rectangular box A, has height of x units, length of y units and width of z units, where x, y, and z are positive integers. A second rectangular box B, has each of its dimensions - height, length and width, 50 percent smaller than that of rectangular box A. If the surface ares of rectangular box B is 2.5 unit^2, what is the volume of rectangular box A?

A. 1/4 unit^3
B. 1 unit^3
C. 2 unit^3
D. 4 unit^3
E. 10 unit^3

SA of a rectangular box: 2(LW+LH+WH)
V of a rectangular box: LWH

SA of B:
2(0.5*0.5(xy)+0.5*0.5(xz)+0.5*0.5(yz))=2.5
2(0.5*0.5(xy+xz+yz)=2.5
2*1/4(xy+xz+yz)=2.5
(xy+xz+yz)=2.5*2=5
(xy+xz+yz)=(2*1+2*1+1*1)=5
(x,y,z)=(2,1,1)

V of A: xyz=2*1*1=2

Ans (C)
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Re: A certain rectangular box A, has height of x units, length of y units [#permalink]
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Re: A certain rectangular box A, has height of x units, length of y units [#permalink]
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