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Bunuel
A certain ship floats with 3/5 of its weight above the water. What is the ratio of the ship’s submerged weight to its exposed weight?

A. 3:8
B. 2:5
C. 3:5
D. 2:3
E. 3:2
Let total weight = 5
Weight above water (exposed) = 3
Weight submerged in water = 2

Required ration = 2:3

Answer: Option D


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Step 1: Define variables
Let the total weight of the ship be W.

Step 2: Determine submerged and exposed weights
- The ship floats with 3/5 of its weight above the water.
→ Exposed weight = (3/5)W
- The remaining weight is submerged:
→ Submerged weight = W - (3/5)W = (2/5)W

Step 3: Find the ratio of submerged weight to exposed weight
Ratio = (Submerged weight) : (Exposed weight)
= (2/5)W : (3/5)W
= 2:3

Thus, the correct answer is (D) 2:3.
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Weight above water= exposed weight= 3/5
Submerged weight=1-(3/5)= 2/5

Submerged weight: exposed weight= (2/5):(3/5)= 2:3

Answer: D
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Method 1
Exposed = 3/5
Submerged = 1-3/5 = 2/5
Submerged/Exposed = 2/3 OR 2:3

Method 2
Submerged < Exposed, so numerator should be smaller.
E. 3:2 reject

Total should be a factor of 5
A. 3:8 3+8 = 11, reject
B. 2:5 2+5 = 7, reject
C. 3:5 3+5 = 8, reject
D. 2:3 2+3 = 5

Answer D

Bunuel
A certain ship floats with 3/5 of its weight above the water. What is the ratio of the ship’s submerged weight to its exposed weight?

A. 3:8
B. 2:5
C. 3:5
D. 2:3
E. 3:2


­
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Explanation

Step 1: Understand the situation
The ship floats with 3/5 of its weight above the water, meaning 2/5 is submerged (since the total weight is 1 or 5/5).

Submerged weight: \(\frac{2}{5}\)
Exposed weight:\(\frac{3}{5}\)

Step 2: Calculate the ratio
The ratio of the submerged weight to the exposed weight is:

Submerged weight : Exposed weight = \(\frac{2}{5 }\) : \(\frac{3}{5}\)

Step 3: Simplify the ratio
Divide both parts of the ratio by 1/5:

\(\frac{2}{5}\) ÷ \(\frac{1}{5 }\) : \(\frac{3}{5}\) ÷ \(\frac{1}{5}\) = 2 : 3


Final Answer:
The ratio of the ship’s submerged weight to its exposed weight is (D) 2:3.
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