Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
17 Oct 2011, 21:13
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
59% (03:15) correct
41%
(03:40)
wrong
based on 237
sessions
History
Date
Time
Result
Not Attempted Yet
A certain sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $12.4 more than that received by B, find the total amount shared by A, B and C.
A. $345.20
B. $386.40
C. $520.30
D. $446.40
E. None
A. $345.20
B. $386.40
C. $520.30
D. $446.40
E. None
va95
Joined: 24 Dec 2016
Last visit: 19 Jun 2025
Posts: 60
Given Kudos: 153
Location: Armenia
Concentration: Statistics
Schools: Duke Fuqua HBS '26 Wharton '26
GMAT 1: 720 Q49 V40
GMAT 2: 770 Q50 V47
GPA: 3.4
WE:Consulting (Consulting)
Products:
01 Jul 2017, 15:16
Kudos
Bookmarks
D
The problem is not hard at all, if you get the logic of it
If A has \(\frac{1}{3}\) of B and C, this means that B and C together have \(\frac{3}{3}\) . So A has 1 peace, B and C have 3 peaces, overall A has \(\frac{1}{4}\) of the total share. If we apply similar logic to B, B has\(\frac{2}{9}\). Now we can make an equality.
\(\frac{1}{4}\)x - \(\frac{1}{9}\)x = 12.4
\(\frac{(9-8)}{36}\)x = 12.4
\(\frac{1}{36}\)x = 12.4
x= 12.4*36=446.4
Hope that helped
The problem is not hard at all, if you get the logic of it
If A has \(\frac{1}{3}\) of B and C, this means that B and C together have \(\frac{3}{3}\) . So A has 1 peace, B and C have 3 peaces, overall A has \(\frac{1}{4}\) of the total share. If we apply similar logic to B, B has\(\frac{2}{9}\). Now we can make an equality.
\(\frac{1}{4}\)x - \(\frac{1}{9}\)x = 12.4
\(\frac{(9-8)}{36}\)x = 12.4
\(\frac{1}{36}\)x = 12.4
x= 12.4*36=446.4
Hope that helped
General Discussion
17 Oct 2011, 22:29
Kudos
Bookmarks
stoy4o
A = 1/3 (B+C) => C = 3A - B ---(1)
B = 2/7 (A+C) => C = 3.5 B - A --(B)
A-B = $12.4
A = 12.4+B
(1)===> C = (37.2)+3B - B = 2B+37.2 ==> 2B-C = -37.2 ---(3)
(2)===> C = 3.5 B - B-12.4 = 2.5B-12.4==>2.5B-C = 12.4 ---(4)
from (4) and (3) 0.5B = 49.6
B = $99.2
A= $111.6
C =334.8-99.2=$235.6
Ans $446.4 (D)
