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27 Jan 2022, 05:45
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C
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Difficulty:
65%
(hard)
Question Stats:
59% (02:19) correct
41%
(01:41)
wrong
based on 130
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A certain thermometer measured the temperature in City X in degreed Fahrenheit every day for one month, and found that the range of temperatures was 21 degrees. If, subsequently, it was discovered that the thermometer always overstated the temperature by 15%, what would the approximate range of measurements have been, in degrees, if the temperatures had been measured accurately?
(A) 15
(B) 17
(C) 18
(D) 21
(E) 24
(A) 15
(B) 17
(C) 18
(D) 21
(E) 24
31 Jan 2022, 18:12
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Bunuel
Breaking Down the Info:
Set the minimum as x, and the maximum as y. The given range is \(y - x = 21\).
Since everything is overstated by 15%, our new range is \(\frac{x}{115\%}\) to \(\frac{y}{115\%}\).
Thus the range is \(\frac{y}{115\%} - \frac{x}{115\%} = \frac{y - x }{ 115\%} = \frac{21}{115\%}\).
We could do long division here to find (21/1.15) is slightly more than 18. (Or see 1.15*20 = 23, and 21 is 2 less which is less than 2 of 1.15's)
Answer: C
PRI23YA
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13 Feb 2022, 22:02
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When Multiplied with a constant x, SD changes by x factor.
.15*21= 3.15. 21-2.15=17.85F
If all the temps are multiplied by SD factor, the range also gets affected by SD factor and becomes 17.85~18
.15*21= 3.15. 21-2.15=17.85F
If all the temps are multiplied by SD factor, the range also gets affected by SD factor and becomes 17.85~18
