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01 Dec 2025, 23:27
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
72% (01:15) correct
28%
(01:04)
wrong
based on 180
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A certain travel agency organizes sightseeing tours. Each client may select the cities she wishes to visit and the order in which she visits them. If each tour must include exactly 4 cities, and if there are exactly 10 cities available, how many different tours are possible?
A. 24
B. 210
C. 420
D. 2,400
E. 5,040
A. 24
B. 210
C. 420
D. 2,400
E. 5,040
02 Dec 2025, 00:09
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Given that the order matters, this is a permutations problem.
10!/(10-4)! which is equal to 5040
Hence, correct answer is E.
Please let me know if this is incorrect, thanks!
10!/(10-4)! which is equal to 5040
Hence, correct answer is E.
Please let me know if this is incorrect, thanks!
Bunuel
02 Dec 2025, 09:30
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Bunuel
The number of city choices available = 10
The number of cities to be choosen for tour = 4
Choosing 4 cities from 10 = 10C4
Arranging the order in which the four cities are visited = 4!
= 10C4 * 4!
= [(10*9*8*7)/(4*3*2*1)] * (4*3*2*1)
= 10*9*8*7
= 5040
Option E
