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I took 4 minutes to do this. While it was correct in the end, I used the method of noting down 1.2.3.4.5 and 2 columns Day and night. Then checking for day at once and marking the ones not possible, then checking for night and marking similarly. Is that the rigt approach? How could this be made quick?
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I took 4 minutes to do this. While it was correct in the end, I used the method of noting down 1.2.3.4.5 and 2 columns Day and night. Then checking for day at once and marking the ones not possible, then checking for night and marking similarly. Is that the rigt approach? How could this be made quick?
This question can be solved very quickly with the right reasoning.

First, the two key limits are:

  • No more than two oxidizers per shift
  • No more than two monomers per shift

The day shift already has two monomers, and the night shift already has two oxidizers.

So, any chemical that is either an oxidizer or a monomer cannot be added to both shifts.

That means for the “either shift” column, we are looking for something that is neither an oxidizer nor a monomer.

From the list, only Phenol and Nickel carbonyl meet that condition.

Now, the day shift has a total health score of 10. Nickel’s health is 4, which would make it 14, exceeding the limit of 13. Therefore, Nickel cannot go to the day shift, leaving only Phenol for either shift.

Since we already know that Nickel cannot go to the day shift, let’s check whether it can go to the night shift. The night shift has a reactivity total of 7, and Nickel’s reactivity is 3, making the total 10, which exceeds the limit of 9. So Nickel cannot go to the night shift either.

So, as you can see, you only need to first reason correctly and then just to check for two chemical only.
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