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07 Oct 2020, 09:00
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B
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70% (02:02) correct
30%
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A circle, shown above, contains 4 identical squares. If each square has a side length equal to 2, what is the radius of the circle?
A. 4
B. \(\frac{\sqrt{85}}{2}\)
C. 5
D. 6
E. \(\sqrt{85}\)
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Untitled.png [ 20.8 KiB | Viewed 2417 times ]
07 Oct 2020, 09:19
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Bunuel
Similar question, which could help in solving this problem: https://gmatclub.com/forum/what-is-the- ... 26929.html
yashikaaggarwal
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07 Oct 2020, 09:33
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I will solve this by approximation.
since the Diagram (red line) is longer than 4 sides of squares in the circle, Each Having length equal to 2
So the diagram is slightly bigger than 8 but less than 10,so radius will be bigger than 4 and less than 5
we can eliminate options A, C, D and E (4,5,6 and 9.2)
Answer has to be B
since the Diagram (red line) is longer than 4 sides of squares in the circle, Each Having length equal to 2
So the diagram is slightly bigger than 8 but less than 10,so radius will be bigger than 4 and less than 5
we can eliminate options A, C, D and E (4,5,6 and 9.2)
Answer has to be B
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Circle.png [ 19.48 KiB | Viewed 2219 times ]
