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A class consists of 12 girls and 20 boys. One quarter of the girls in

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A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 31 Jul 2018, 00:59
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A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?


(A) \(\frac{3}{32}\)

(B) \(\frac{9}{32}\)

(C) \(\frac{3}{8}\)

(D) \(\frac{23}{32}\)

(E) \(\frac{29}{32}\)

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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 31 Jul 2018, 01:05
one quarter of girls have blue eyes i.e 3 girls have blue eyes .

girl with no blue eyes =12-3 =9

Total outcome =20+12=32

Required probability = (9/32)
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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 31 Jul 2018, 01:09
Bunuel wrote:
A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?


(A) \(\frac{3}{32}\)

(B) \(\frac{9}{32}\)

(C) \(\frac{3}{8}\)

(D) \(\frac{23}{32}\)

(E) \(\frac{29}{32}\)



Total number of students = 32
One quarter of the girls in the class have blue eyes =12/4=3
required probability = 9/32
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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 31 Jul 2018, 03:32
Bunuel wrote:
A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?


Total students = 12 girls + 20 boys = 32
Number of girls with blue eyes = One quarter of the 12 girls = 1/4 * 12 = 3
Number of girls who do not have blue eyes = 12 - 3 = 9

Required probability = Number of girls who do not have blue eyes / Total students = 9 / 32

Hence, B.
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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 10 Aug 2018, 19:11
Bunuel wrote:
A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?


(A) \(\frac{3}{32}\)

(B) \(\frac{9}{32}\)

(C) \(\frac{3}{8}\)

(D) \(\frac{23}{32}\)

(E) \(\frac{29}{32}\)


Since ¼ of the 12 girls have blue eyes, ¼ x 12 = 3 girls have blue eyes. So 9 girls don’t have blue eyes. Since there are 12 + 20 = 32 students in the class, the probability that a child is a girl who does not have blue eyes is 9/32.

Answer: B
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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 11 Jan 2019, 12:06
Hi All,

We're told that a class consists of 12 girls and 20 boys. One-quarter of the girls in the class have blue eyes. We're asked for the probability that a randomly selected child is a girl who does NOT have blue eyes. This question comes down to some basic organization and Arithmetic.

From the first sentence, we know that there are 12 girls and 20 boys.

With the second sentence, we can break the 12 girls down into 2 groups: those with blue eyes and those that don't have blue eyes:
(1/4)(12) = 3 with blue eyes
12 - 3 = 9 that don't have blue eyes

The number of girls who DON'T have blue eyes.... out of the total number of students in the class... is 9/32

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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in   [#permalink] 11 Jan 2019, 12:06
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