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A class consists of 12 girls and 20 boys. One quarter of the girls in

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A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 30 Jul 2018, 23:59
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A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?


(A) \(\frac{3}{32}\)

(B) \(\frac{9}{32}\)

(C) \(\frac{3}{8}\)

(D) \(\frac{23}{32}\)

(E) \(\frac{29}{32}\)

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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 31 Jul 2018, 00:05
one quarter of girls have blue eyes i.e 3 girls have blue eyes .

girl with no blue eyes =12-3 =9

Total outcome =20+12=32

Required probability = (9/32)
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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 31 Jul 2018, 00:09
Bunuel wrote:
A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?


(A) \(\frac{3}{32}\)

(B) \(\frac{9}{32}\)

(C) \(\frac{3}{8}\)

(D) \(\frac{23}{32}\)

(E) \(\frac{29}{32}\)



Total number of students = 32
One quarter of the girls in the class have blue eyes =12/4=3
required probability = 9/32
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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 31 Jul 2018, 02:32
Bunuel wrote:
A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?


Total students = 12 girls + 20 boys = 32
Number of girls with blue eyes = One quarter of the 12 girls = 1/4 * 12 = 3
Number of girls who do not have blue eyes = 12 - 3 = 9

Required probability = Number of girls who do not have blue eyes / Total students = 9 / 32

Hence, B.
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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in  [#permalink]

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New post 10 Aug 2018, 18:11
Bunuel wrote:
A class consists of 12 girls and 20 boys. One quarter of the girls in the class have blue eyes. If a child is selected at random from the class, what is the probability that the child is a girl who does not have blue eyes?


(A) \(\frac{3}{32}\)

(B) \(\frac{9}{32}\)

(C) \(\frac{3}{8}\)

(D) \(\frac{23}{32}\)

(E) \(\frac{29}{32}\)


Since ¼ of the 12 girls have blue eyes, ¼ x 12 = 3 girls have blue eyes. So 9 girls don’t have blue eyes. Since there are 12 + 20 = 32 students in the class, the probability that a child is a girl who does not have blue eyes is 9/32.

Answer: B
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Re: A class consists of 12 girls and 20 boys. One quarter of the girls in &nbs [#permalink] 10 Aug 2018, 18:11
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