GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 19 Nov 2018, 03:30

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

## Events & Promotions

###### Events & Promotions in November
PrevNext
SuMoTuWeThFrSa
28293031123
45678910
11121314151617
18192021222324
2526272829301
Open Detailed Calendar
• ### How to QUICKLY Solve GMAT Questions - GMAT Club Chat

November 20, 2018

November 20, 2018

09:00 AM PST

10:00 AM PST

The reward for signing up with the registration form and attending the chat is: 6 free examPAL quizzes to practice your new skills after the chat.
• ### The winning strategy for 700+ on the GMAT

November 20, 2018

November 20, 2018

06:00 PM EST

07:00 PM EST

What people who reach the high 700's do differently? We're going to share insights, tips and strategies from data we collected on over 50,000 students who used examPAL.

# A club sold an average (arithmetic mean) of 92 raffle tickets per memb

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 50661
A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

29 Jun 2017, 03:21
3
5
00:00

Difficulty:

25% (medium)

Question Stats:

71% (01:07) correct 29% (01:27) wrong based on 185 sessions

### HideShow timer Statistics

A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?

(A) 1 : 1
(B) 1 : 2
(C) 1 : 3
(D) 2 : 1
(E) 3 : 1

_________________
Director
Joined: 18 Aug 2016
Posts: 625
Concentration: Strategy, Technology
GMAT 1: 630 Q47 V29
GMAT 2: 740 Q51 V38
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

29 Jun 2017, 03:26
1
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?

(A) 1 : 1
(B) 1 : 2
(C) 1 : 3
(D) 2 : 1
(E) 3 : 1

Male : Average : Female
96 : 92 : 84

92-84: 96-92
8:4
2:1
D
_________________

We must try to achieve the best within us

Thanks
Luckisnoexcuse

Senior PS Moderator
Joined: 26 Feb 2016
Posts: 3307
Location: India
GPA: 3.12
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

29 Jun 2017, 04:06
1
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?

(A) 1 : 1
(B) 1 : 2
(C) 1 : 3
(D) 2 : 1
(E) 3 : 1

Let x be the female members and y the male members.

Since we are given that
-> the average number of raffle tickets sold among female members was 84
-> the average number of raffle tickets sold among female members was 96

From the question stem we can deduce the following :
$$\frac{(84x + 96y)}{(x+y)} = 92$$
$$84x + 96y = 92x + 92y$$
$$4y = 8x$$
$$\frac{y}{x} = \frac{2}{1}$$

Female members : Male members are in ratio 2:1(Option D)
_________________

You've got what it takes, but it will take everything you've got

Manager
Joined: 03 Feb 2017
Posts: 75
Location: Australia
GMAT 1: 720 Q48 V40
A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

29 Jun 2017, 05:20
The average of 92 is closer to 96 (male) than 84 (female)
So there is more weightage on male number than female number which pulls the total average more towards Male average, so answer has to be D or E

using alligation: M:F = $$\frac{(Total average - Female average)}{(Male average - Total Average)}$$ = $$\frac{(92-84)}{(96-92)}$$
=$$\frac{8}{4}$$ = $$\frac{2}{1}$$

Board of Directors
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4224
Location: India
GPA: 3.5
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

29 Jun 2017, 08:10
1
1
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?

(A) 1 : 1
(B) 1 : 2
(C) 1 : 3
(D) 2 : 1
(E) 3 : 1
Attachment:

Untitled.jpg [ 11.92 KiB | Viewed 3089 times ]

Thus, the ratio will be 8 : 4 = 2 : 1

_________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )

Intern
Joined: 27 Dec 2016
Posts: 14
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

29 Jun 2017, 08:20
Abhishek009 wrote:
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?

(A) 1 : 1
(B) 1 : 2
(C) 1 : 3
(D) 2 : 1
(E) 3 : 1
Attachment:
Untitled.jpg

Thus, the ratio will be 8 : 4 = 2 : 1

awesome bro. need to develop this kind of thinking to attack problems.
although I know the concept, I almost fail in application when required.
Intern
Joined: 07 Aug 2016
Posts: 13
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

29 Jun 2017, 19:54
Simple put nos In given option and you will be able to eliminate wrong ones and get the correct one as D

Sent from my iPhone using GMAT Club Forum
Senior Manager
Joined: 28 Jun 2015
Posts: 293
Concentration: Finance
GPA: 3.5
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

29 Jun 2017, 20:49
$$M:F = (92-84) : (96-92) = 8:4 = 2:1$$. Ans - D.
_________________

I used to think the brain was the most important organ. Then I thought, look what’s telling me that.

Director
Joined: 09 Mar 2017
Posts: 516
Location: India
Concentration: Marketing, Organizational Behavior
WE: Information Technology (Computer Software)
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

30 Jun 2017, 22:19
1
D.
84f + 96m =92(f+m)
Divide the eqn on both sides by f
Let (m/f) be x
84 + 96x = 92 + 92x
X = 2:1
(D)
_________________

------------------------------
"Trust the timing of your life"
Hit Kudus if this has helped you get closer to your goal, and also to assist others save time. Tq

Intern
Joined: 21 Aug 2018
Posts: 10
Location: India
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

02 Nov 2018, 06:07
VP
Joined: 09 Mar 2016
Posts: 1093
A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

02 Nov 2018, 10:23
pushpitkc wrote:
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?

(A) 1 : 1
(B) 1 : 2
(C) 1 : 3
(D) 2 : 1
(E) 3 : 1

Let x be the female members and y the male members.

Since we are given that
-> the average number of raffle tickets sold among female members was 84
-> the average number of raffle tickets sold among female members was 96

From the question stem we can deduce the following :
$$\frac{(84x + 96y)}{(x+y)} = 92$$
$$84x + 96y = 92x + 92y$$
$$4y = 8x$$
$$\frac{y}{x} = \frac{2}{1}$$

Female members : Male members are in ratio 2:1(Option D)

pushpitkc if question is to find the ratio of the number of male members to the number of female members in the club?

And if $$x$$ the number the female members and $$y$$ is the# of male members.

how is it possible that answer is D ?

it should be vice versa 1 : 2 based on this $$4y = 8x$$ ad not 2:1

can you explain
PS Forum Moderator
Status: It always seems impossible until it's done.
Joined: 16 Sep 2016
Posts: 383
GMAT 1: 740 Q50 V40
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

02 Nov 2018, 11:02
1
dave13,

Female is X and male is Y in his solution... So male to female will be y:x which is what is used. 2:1

I think you're mixing the variables up. Try solving again from scratch with m & f

Best
G
Director
Joined: 19 Oct 2013
Posts: 502
Location: Kuwait
GPA: 3.2
WE: Engineering (Real Estate)
A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

Updated on: 02 Nov 2018, 11:49
1
Hi dave13

This can be solved in a way similar to mixture questions using allegation method

male = x
Female = y

Using allegation method, here the desired is the average

Desired - y/x - desired

So 92 - 84 = 8

96 - 92 = 4

x/y = 8/4 = 2/1

https://gmatclub.com/forum/tips-and-tri ... 51906.html

Posted from my mobile device

Originally posted by Salsanousi on 02 Nov 2018, 11:17.
Last edited by Salsanousi on 02 Nov 2018, 11:49, edited 1 time in total.
VP
Joined: 09 Mar 2016
Posts: 1093
A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

02 Nov 2018, 11:39
priyamba wrote:

priyamba , I got it thanks to great people on GC

Female is X and male is Y in his solution... So male to female will be y:x which is what is used. 2:1

So when we get 4Y=8X to find ratio of male to female solve for Y ---> i.e. Y = $$\frac{8x}{4}$$ ----> y = 2x

hence ratio of males to females is 2x to X i.e. 2:1

Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 4170
Location: United States (CA)
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb  [#permalink]

### Show Tags

03 Nov 2018, 16:56
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?

(A) 1 : 1
(B) 1 : 2
(C) 1 : 3
(D) 2 : 1
(E) 3 : 1

We are given that a club sold an average (arithmetic mean) of 92 raffle tickets per member, that among the female members, the average number sold was 84, and that among the male members, the average number sold was 96. We can let f = the number of females and m = the number of males, and we can create the following weighted average equation:

92 = (84f + 96m)/(m + f)

92m + 92f = 84f + 96m

8f = 4m

2f = m

2 = m/f

_________________

Scott Woodbury-Stewart
Founder and CEO

GMAT Quant Self-Study Course
500+ lessons 3000+ practice problems 800+ HD solutions

Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb &nbs [#permalink] 03 Nov 2018, 16:56
Display posts from previous: Sort by