Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL.
Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.
A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
29 Jun 2017, 03:21
3
9
00:00
A
B
C
D
E
Difficulty:
35% (medium)
Question Stats:
71% (01:13) correct 29% (01:29) wrong based on 226 sessions
HideShow timer Statistics
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
29 Jun 2017, 03:26
2
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
29 Jun 2017, 04:06
1
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?
(A) 1 : 1 (B) 1 : 2 (C) 1 : 3 (D) 2 : 1 (E) 3 : 1
Let x be the female members and y the male members.
Since we are given that -> the average number of raffle tickets sold among female members was 84 -> the average number of raffle tickets sold among female members was 96
From the question stem we can deduce the following : \(\frac{(84x + 96y)}{(x+y)} = 92\) \(84x + 96y = 92x + 92y\) \(4y = 8x\) \(\frac{y}{x} = \frac{2}{1}\)
Female members : Male members are in ratio 2:1(Option D) _________________
You've got what it takes, but it will take everything you've got
A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
29 Jun 2017, 05:20
The average of 92 is closer to 96 (male) than 84 (female) So there is more weightage on male number than female number which pulls the total average more towards Male average, so answer has to be D or E
using alligation: M:F = \(\frac{(Total average - Female average)}{(Male average - Total Average)}\) = \(\frac{(92-84)}{(96-92)}\) =\(\frac{8}{4}\) = \(\frac{2}{1}\)
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
29 Jun 2017, 08:10
1
1
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?
(A) 1 : 1 (B) 1 : 2 (C) 1 : 3 (D) 2 : 1 (E) 3 : 1
Attachment:
Untitled.jpg [ 11.92 KiB | Viewed 3595 times ]
Thus, the ratio will be 8 : 4 = 2 : 1 Answer will be (D) _________________
Thanks and Regards
Abhishek....
PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
29 Jun 2017, 08:20
Abhishek009 wrote:
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?
(A) 1 : 1 (B) 1 : 2 (C) 1 : 3 (D) 2 : 1 (E) 3 : 1
Attachment:
Untitled.jpg
Thus, the ratio will be 8 : 4 = 2 : 1 Answer will be (D)
awesome bro. need to develop this kind of thinking to attack problems. although I know the concept, I almost fail in application when required.
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
30 Jun 2017, 22:19
1
D. 84f + 96m =92(f+m) Divide the eqn on both sides by f Let (m/f) be x 84 + 96x = 92 + 92x X = 2:1 (D)
_________________
------------------------------ "Trust the timing of your life" Hit Kudus if this has helped you get closer to your goal, and also to assist others save time. Tq
A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
02 Nov 2018, 10:23
pushpitkc wrote:
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?
(A) 1 : 1 (B) 1 : 2 (C) 1 : 3 (D) 2 : 1 (E) 3 : 1
Let x be the female members and y the male members.
Since we are given that -> the average number of raffle tickets sold among female members was 84 -> the average number of raffle tickets sold among female members was 96
From the question stem we can deduce the following : \(\frac{(84x + 96y)}{(x+y)} = 92\) \(84x + 96y = 92x + 92y\) \(4y = 8x\) \(\frac{y}{x} = \frac{2}{1}\)
Female members : Male members are in ratio 2:1(Option D)
pushpitkc if question is to find the ratio of the number of male membersto the number of female members in the club?
And if \(x\) the number the female members and \(y\) is the# of male members.
how is it possible that answer is D ?
it should be vice versa 1 : 2 based on this \(4y = 8x\) ad not 2:1
Re: A club sold an average (arithmetic mean) of 92 raffle tickets per memb
[#permalink]
Show Tags
03 Nov 2018, 16:56
Bunuel wrote:
A club sold an average (arithmetic mean) of 92 raffle tickets per member. Among the female members, average number sold was 84, and among the male members, the average number sold was 96. What was the ratio of the number of male members to the number of female members in the club?
(A) 1 : 1 (B) 1 : 2 (C) 1 : 3 (D) 2 : 1 (E) 3 : 1
We are given that a club sold an average (arithmetic mean) of 92 raffle tickets per member, that among the female members, the average number sold was 84, and that among the male members, the average number sold was 96. We can let f = the number of females and m = the number of males, and we can create the following weighted average equation:
92 = (84f + 96m)/(m + f)
92m + 92f = 84f + 96m
8f = 4m
2f = m
2 = m/f
Answer: D
_________________
Scott Woodbury-Stewart Founder and CEO
GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions
close
71% (01:13) correct 
