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Re: A committee of three students has to be formed. There are
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26 Jul 2014, 12:19
I just get the feeling that all these combinations are really misleading and unecessary to solve this one. Correct answer is 5 not 4 as official answer. 1 possible way  when Saul & Paul are out you have Jessica, Jane and Joan 3 ways when Sean is added to committe and combines: 1. Sean, Jessica, Joan 2. sean, jessica, jane & 3. Sean, joan, jane 1 way when paul is in the comitte  sean joan jessica Adding those up it's 5! Am i crazy or what? Posted from GMAT ToolKit



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Re: A committee of three students has to be formed. There are
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26 Jul 2014, 12:33
oanaandries wrote: I just get the feeling that all these combinations are really misleading and unecessary to solve this one. Correct answer is 5 not 4 as official answer. 1 possible way  when Saul & Paul are out you have Jessica, Jane and Joan3 ways when Sean is added to committe and combines: 1. Sean, Jessica, Joan 2. sean, jessica, jane & 3. Sean, joan, jane 1 way when paul is in the comitte  sean joan jessica Adding those up it's 5! Am i crazy or what? Posted from GMAT ToolKitThe committees in red are not possible: Jane cannot be in the committee without Paul. There are only 4 committees possible: {Jane, Paul, Joan} {Jane, Paul, Jessica} {Paul, Jane, Jessica} {Stuart, Joan, Jessica} Please read the whole thread and try to understand the approaches presented there...
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Re: A committee of three students has to be formed. There are
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05 Dec 2014, 23:35
can any one explain it with A B C D E
as A and B cant be together and B and C cant be separate So we can form BCD, BCE and ADE what will be the another one I am missing



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Re: A committee of three students has to be formed. There are
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06 Dec 2014, 04:02
anceer wrote: can any one explain it with A B C D E
as A and B cant be together and B and C cant be separate So we can form BCD, BCE and ADE what will be the another one I am missing hi, B and C can be separate. the question sates that if C is selected then B has to be there. but if B is selected than C may or may not be there. so, considering this in mind. the case you're missing is BDE. i hope it helps.



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Re: A committee of three students has to be formed. There are
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06 Dec 2014, 05:40
Thanks Manpreet now I got the twist... It was confusing..



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Re: A committee of three students has to be formed. There are
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13 Mar 2016, 06:39
scheol79 wrote: A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
A. 3 B. 4 C. 5 D. 6 E. 8
m10 q25 Given: A, B, C, D, AND E C and D are not together If A, then C The committee consists of three with A we have to include C; the third person can be B or E => (ACB) OR (ACE) with B , we have to choose from C, D, E; in this C and D are not together CE or DE=>(BCE) or (BDE) with C, we have to choose from D and E => not possible Therefore, there are only 4 possibilities.



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Re: A committee of three students has to be formed. There are
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16 Mar 2016, 19:13
There are two cases 1. When Jane serves in the committee. That implies Paul is in the committee. The remaining person can be chosen in 2 ways. 2. When Jane does not serve. In this case either Paul or Stuart can be the first member. There is just one way of selecting the remaining 2 members in each case. So a total of 2 ways when Jane does not serve Total = 2+2=4
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Re: A committee of three students has to be formed. There are
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11 Jun 2018, 09:22
scheol79 wrote: A committee of three students has to be formed. There are five candidates: Jane, Joan, Paul, Stuart, and Jessica. If Paul and Stuart refuse to be in the committee together and Jane refuses to be in the committee without Paul, how many committees are possible?
A. 3 B. 4 C. 5 D. 6 E. 8
m10 q25 Three Possible cases: i)Committee has Paul & Jane, hence the third person can be selected is out of Joan & Jessica = 2 ways ii)Committee has Paul but no Jane, hence the second person & third person can be selected out of again, Joan & Jessica, = 1 way iii)Committee has Stuart, hence no Paul & hence no Jane, only Joan & Jessica can be selected = 1 way Total # ways to form the committee = 2+1+1 = 4 Answer B. Thanks, GyM
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Re: A committee of three students has to be formed. There are
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11 Jun 2018, 09:44
Guys I think you make it more complicate
Here is my approach: Without restrictions  we can make 5C3=10 committees
Subtract Paul's restrictions: 1) Paul, Stewart, Jane 2) Paul, Stewart, Joan 3) Paul, Stewart, Jessica
Subtract Jane's restrictions: 1) Jane, Joan, Stuart 2)Jane, Joan, Jessica 3) Jane, Stuart, Jessica
only 4 committees are left



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Re: A committee of three students has to be formed. There are
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13 Jun 2018, 06:09
It seemed to me very easy question (maybe because not a big number of options are there). Since Paul and Stuart cannot be together and Jane will not be in committee without Paul, lets consider first Paul. 1.Paul + Jane + Joan 2.Joan+Paul+jess 3.paul+jess+jane Now, consider stuard, 4.Stuart+ jess+jane 4 in total, answer is B



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Re: A committee of three students has to be formed. There are
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11 Jul 2019, 17:14
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Re: A committee of three students has to be formed. There are
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