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costcosized
Having difficulty arriving to x=10(p+r) ... anyone able to provide additional clarification?

Hello costcosized,

I hope you understood the solution till this stage. With this assumption, let’s look at the immediate step preceding the equation, about which you have a question.
The equation that precedes it is,

1000 (1-\(\frac{r}{100}\)) + x = 1000 (1 + \(\frac{p}{ 100}\))

Let us open up the brackets by multiplying the number 1000 with each of the terms inside the brackets. When we do this,

LHS = 1000(1-\(\frac{r}{100}\)) + x = 1000*1 – 1000*\(\frac{r}{100}\) + x = 1000 – 10r + x AND

RHS = 1000(1+\(\frac{p}{100}\)) = 1000*1 + 1000*\(\frac{p}{100}\) = 1000 + 10p.

Therefore, we have,
1000 – 10r + x = 1000 + 10p.

You see that the 1000 on both sides cancel out. Transferring -10r from the LHS to the RHS, we have,
x = 10p + 10r.
10 is a common factor on the RHS, so, x = 10(p+r).

Hope that clarifies your doubt! If you have any other questions on this, please feel free to post your query and I’d be happy to respond.
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CrackVerbalGMAT
This is awesome! I used the exact same approach to the point that even I ended up using "x" as the variable. LOL!
Just praising how awesome your courses are !

Thank you from a student of your course!

CrackVerbalGMAT
In this question, although it may look like plugging values for ‘p’ and ‘r’ could be the easier way to solve, analyzing the question stem is the better and effective way. Plugging values might actually prove counter productive here.

Let us assume ‘x’ new employees joined the company during the year 2011. We also know that ‘p’ percent of 1000 employees left the company. Therefore, the number of employees in the company should be,
1000 (1 – \(\frac{p}{100}\)) + x.

But, the question also says that, by the end of 2011, the number of employees of the company had increased by ‘r’ percent. This means, it should have become 1000 (1 + \(\frac{r}{100}\)).

Therefore,

1000 (1-\(\frac{p}{100}\)) + x = 1000 (1+\(\frac{r}{100}\)).

On simplifying the above equation, we get,

x = 10 p + 10 r, which can also be written as

x = 10 (p+r).

So, essentially, if we are to calculate the number of employees who joined the company in 2011 (i.e. x), we need the value of (p+r).

Statement I, therefore, is clearly sufficient. The possible answers are A or D. Options B, C and E can be eliminated.

Statement II says that if we interchange the positions of ‘p’ and ‘r’ in the equation above, x will still remain same. But, that is not sufficient to find the VALUE of x.

1000 (1-\(\frac{r}{100}\)) + x = 1000 (1 + \(\frac{p}{100}\)), which, on simplification yields

x = 10 (p + r).

But, since we do not know the values of p and r, we will not be able to calculate the value of x uniquely. Statement II alone is insufficient.
The correct answer option is A.

Had we taken values for the first statement, we would have to deal with an assortment of them. Instead, the idea was to break down the question stem to obtain an equation/expression, from which to figure out the variable/combination of variables to look for in the statements. It made it easy for us by telling us WHAT to look for in the statements.

Hope this helps!
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