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12 Nov 2025, 00:27
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C
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Difficulty:
25%
(medium)
Question Stats:
73% (01:19) correct
27%
(01:11)
wrong
based on 56
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A container has red, blue and green balls, and the number of green balls is less than 15. How many green balls are in the container?
(1) The ratio of red to blue balls is 6 to 5
(2) There are twice as many green balls as red balls in the container.
(1) The ratio of red to blue balls is 6 to 5
(2) There are twice as many green balls as red balls in the container.
12 Nov 2025, 00:59
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Statement (1): Gives only the ratio of red to blue balls.
It says nothing about green balls. Not sufficient.
Statement (2): Gives the relationship between green and red balls but no actual numbers.
Not sufficient.
Even together, we know only ratios but not total numbers.
Still can’t find how many green balls are there.
Answer: (E) Statements (1) and (2) together are not sufficient.
It says nothing about green balls. Not sufficient.
Statement (2): Gives the relationship between green and red balls but no actual numbers.
Not sufficient.
Even together, we know only ratios but not total numbers.
Still can’t find how many green balls are there.
Answer: (E) Statements (1) and (2) together are not sufficient.
12 Nov 2025, 03:26
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I think C
R + B + G = Total
We want to find G (key point to remember is G < 15 and B, G, and R have to be a positive integers)
(1) R / B = 6 / 5
This along isn't sufficient as we cannot figure out the total OR the G. For example, total can be 12 with 6 R, 5 B, and 1 G. Alternatively, total can be 13 with 6 R, 5 B, and 2 G. And any number of other solutions. NOT SUFFICIENT.
(2) G = 2R
This still doesn't give us a unique solution of G. Again, we can apply virtually infinite number of different cases. NOT SUFFICIENT.
(1) + (2)
We can sub in R = (1/2)*G from (2) into the ratio from (1)
(1/2) * G / B = 6 / 5
G = (6 * 2 * B) / 5
From this, we find that G has to be a multiple of 5 AND < 15, implying that B has to be a multiple of 5 (as 6 and 2 are not multiples of 5)
The only solution that satisfies this B = 1, G = (6 * 2 * 5) / 5 = 12
Going to B = 10 (next multiple of 5) -> G = (6 * 2 * 10) / 5 = 24, which is not possible
Hence, there is a unique solution so the combination of statements is SUFFICIENT
C
R + B + G = Total
We want to find G (key point to remember is G < 15 and B, G, and R have to be a positive integers)
(1) R / B = 6 / 5
This along isn't sufficient as we cannot figure out the total OR the G. For example, total can be 12 with 6 R, 5 B, and 1 G. Alternatively, total can be 13 with 6 R, 5 B, and 2 G. And any number of other solutions. NOT SUFFICIENT.
(2) G = 2R
This still doesn't give us a unique solution of G. Again, we can apply virtually infinite number of different cases. NOT SUFFICIENT.
(1) + (2)
We can sub in R = (1/2)*G from (2) into the ratio from (1)
(1/2) * G / B = 6 / 5
G = (6 * 2 * B) / 5
From this, we find that G has to be a multiple of 5 AND < 15, implying that B has to be a multiple of 5 (as 6 and 2 are not multiples of 5)
The only solution that satisfies this B = 1, G = (6 * 2 * 5) / 5 = 12
Going to B = 10 (next multiple of 5) -> G = (6 * 2 * 10) / 5 = 24, which is not possible
Hence, there is a unique solution so the combination of statements is SUFFICIENT
C
