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03 Jun 2020, 10:57
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B
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A container is completely filled with a sugar solution composed of water and sugar syrup in the ratio of 7:3. The container has 2 holes covered with filters such that from one of the holes only sugar syrup can flow out and from the other hole only water can flow out. The rates of water outflow and sugar syrup outflow from their respective holes are x cubic centimeters per hour and y cubic centimeters per half an hour respectively, such that x:y = 5:1. If the water from the solution can be drained out completely in 14 hours from the hole, how much time in hours would it take the container to be empty if both the holes are opened simultaneously?
A. 14
B. 15
C. 29
D. 30
E. 44
Are You Up For the Challenge: 700 Level Questions
A. 14
B. 15
C. 29
D. 30
E. 44
Are You Up For the Challenge: 700 Level Questions
yashikaaggarwal
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Updated on: 07 Jun 2020, 11:06
Originally posted by yashikaaggarwal on 03 Jun 2020, 12:21.
Last edited by yashikaaggarwal on 07 Jun 2020, 11:06, edited 1 time in total.
Last edited by yashikaaggarwal on 07 Jun 2020, 11:06, edited 1 time in total.
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Let the container contain 100 litre of sugar solution.
Out of which 70 is water and 30 is sugar syrup
The pipe x drains 5z in an hour.
Draining 70 litre is 70/5z in 14/z hour
Since pipe x drain complete water in 14 hours. 14/z=14
Z=1
Z litre is drained out of pipe y in half an hour.
2Z in an Hour
30 litre will be drained in 30/2z => 15 hours.
Answer should be B
Posted from my mobile device
Out of which 70 is water and 30 is sugar syrup
The pipe x drains 5z in an hour.
Draining 70 litre is 70/5z in 14/z hour
Since pipe x drain complete water in 14 hours. 14/z=14
Z=1
Z litre is drained out of pipe y in half an hour.
2Z in an Hour
30 litre will be drained in 30/2z => 15 hours.
Answer should be B
Posted from my mobile device
W:S = 7:3 => S = 3*W/7
x:y = 5:1 => y = x/5
x cc/hr implies in 14 hrs, it will drain 14x cc of water. So, S = 3*14x/7 = 6x
2x/5 of S is drained out every hour, so 6x will be drained out in 15 hrs.
Ans: 15
x:y = 5:1 => y = x/5
x cc/hr implies in 14 hrs, it will drain 14x cc of water. So, S = 3*14x/7 = 6x
2x/5 of S is drained out every hour, so 6x will be drained out in 15 hrs.
Ans: 15
