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A coordinate plane is shown in the figure..

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A coordinate plane is shown in the figure.. [#permalink]

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A coordinate plane is shown in the figure. A curve can be drawn using the equation "a*f(x) = bx – 2b" (ab ≠ 0). If (1, t) is a point on the curve, then in which quadrant does the point lie?
(1) The curve crosses the y-axis on its positive side.
(2) The curve crosses the x-axis on its positive side.
[Reveal] Spoiler: OA

Last edited by WoundedTiger on 23 May 2014, 01:09, edited 2 times in total.
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Re: A coordinate plane is shown in the figure.. [#permalink]

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For Statement I:
Since (1,t) point lies on the curve, so we have t = b-2b i.e b= -t.
Now since, curve crosses the y-axis on its positive side, so we have b*0-2b = +ve i.e b= -ve.
From above information, as b= -t, so t is +ve. Thus (1,t) lies in quarter 1.

Statement 1 is sufficient

For Statement II:

+ve = b*x - 2b -> Sign of b can't be determined. Hence statement 2 is insufficient.

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Re: A coordinate plane is shown in the figure.. [#permalink]

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New post 23 May 2014, 00:41
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Hi Anujpadia,

Hope it helps :-D

Rgds,
Rajat Jain
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Re: A coordinate plane is shown in the figure.. [#permalink]

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New post 23 Sep 2017, 06:14
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Re: A coordinate plane is shown in the figure..   [#permalink] 23 Sep 2017, 06:14
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