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A country's population increased x% in 2011 and then by y% in 2012.

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Joined: 11 Oct 2017
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Kudos [?]: 6 [0], given: 73

A country's population increased x% in 2011 and then by y% in 2012. [#permalink]

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New post 30 Oct 2017, 16:42
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E

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  45% (medium)

Question Stats:

60% (01:07) correct 40% (01:21) wrong based on 20 sessions

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A country's population increased x% in 2011 and then by y% in 2012. By what percent did the population increase over those two years?

(1) xy = 50

(2) 100x + 100y +xy = 2150


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[Reveal] Spoiler: OA

Kudos [?]: 6 [0], given: 73

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Joined: 05 Aug 2017
Posts: 19

Kudos [?]: 16 [0], given: 19

Location: Viet Nam
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Concentration: International Business, Other
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Re: A country's population increased x% in 2011 and then by y% in 2012. [#permalink]

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New post 30 Oct 2017, 19:22
B is my answer.

2010, A country's population is p
-> P(2011)= (100+x)%.p
P(2012)= [(100+x)%.p].(100+y)%
-> Percent of the population increased over those two years= [P(2012)-P(2010)]/P(2010)= [[(100+x)%.p].(100+y)% -p]/p= [(100+x)/100. (100+y)/100]-1= [100(x+y)+xy]/10000
(1)-> insuff bcuz from xy = 50 we dont know x+y
(2) 100x + 100y +xy = 2150 -> 100(x+y) +xy =2150 -> suff
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Kudos [?]: 132495 [0], given: 12323

Re: A country's population increased x% in 2011 and then by y% in 2012. [#permalink]

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New post 30 Oct 2017, 20:56
ladyrenee95 wrote:
A country's population increased x% in 2011 and then by y% in 2012. By what percent did the population increase over those two years?

(1) xy = 50

(2) 100x + 100y +xy = 2150


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Kudos [?]: 132495 [0], given: 12323

Re: A country's population increased x% in 2011 and then by y% in 2012.   [#permalink] 30 Oct 2017, 20:56
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