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A country's population increased x% in 2011 and then by y% in 2012.

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Joined: 11 Oct 2017
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A country's population increased x% in 2011 and then by y% in 2012.  [#permalink]

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New post 30 Oct 2017, 15:42
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A country's population increased x% in 2011 and then by y% in 2012. By what percent did the population increase over those two years?

(1) xy = 50

(2) 100x + 100y +xy = 2150


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Joined: 05 Aug 2017
Posts: 27
Location: Viet Nam
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Concentration: International Business, Other
GPA: 3.33
WE: Supply Chain Management (Transportation)
Re: A country's population increased x% in 2011 and then by y% in 2012.  [#permalink]

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New post 30 Oct 2017, 18:22
B is my answer.

2010, A country's population is p
-> P(2011)= (100+x)%.p
P(2012)= [(100+x)%.p].(100+y)%
-> Percent of the population increased over those two years= [P(2012)-P(2010)]/P(2010)= [[(100+x)%.p].(100+y)% -p]/p= [(100+x)/100. (100+y)/100]-1= [100(x+y)+xy]/10000
(1)-> insuff bcuz from xy = 50 we dont know x+y
(2) 100x + 100y +xy = 2150 -> 100(x+y) +xy =2150 -> suff
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Re: A country's population increased x% in 2011 and then by y% in 2012.  [#permalink]

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New post 30 Oct 2017, 19:56
ladyrenee95 wrote:
A country's population increased x% in 2011 and then by y% in 2012. By what percent did the population increase over those two years?

(1) xy = 50

(2) 100x + 100y +xy = 2150


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Re: A country's population increased x% in 2011 and then by y% in 2012. &nbs [#permalink] 30 Oct 2017, 19:56
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