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Price =p
discount price = 0.8 p
since he got 20 instead of 15 , therefore 0.8*15*P=Alpha*p*20
Alpha=0.6
the price is 0.6*P
Now he get 20% profit.
CP*1.2 =0.6P
CP=P/2
or P=2*CP
So the price is double the cost price
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Using cost price as the baseline, think of it this way and multiply accordingly:

1. Profit margin

(2. and 3. are interchangeable)

2. Cash discount
3. Bargain pieces

6/5 (20% profit) * 5/4 (20% cash discount) * 4/3 (20 for the price of 15) = 200%

Answer (A)
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Here's how I tried to solve:

What we know?

P2 = bargained price
P1 = discounted price
M = marked price
C = cost
-------------------
What's the question?

M/C =?
-------------------
P2 * 20 = P1 * 15 (Bought 20 papers at the same cost of 15 papers)
P1 = 80M (Discounted 20%, so discounted price was 0.8market price)
P2 = 120C (Bargained price was 20% more than cost or 20% profit)

So here we just replace P1,P2 with known points

120C * 20 = 80M *15
20/15 = 80M/120C
M/C = 4/3* 3/4 = 1 or 100%
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