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10 Mar 2021, 09:00
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71% (02:00) correct
29%
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A dog chase a cat and takes 6 leaps for every 9 leaps of the cat, but 3 leaps of the dog are equal to 5 leaps of the cat. What is the ration of the speeds of the dog and the cat?
(A) 9 : 10
(B) 10 : 9
(C) 24 : 25
(D) 25 : 24
(E) 26 : 25
(A) 9 : 10
(B) 10 : 9
(C) 24 : 25
(D) 25 : 24
(E) 26 : 25
10 Mar 2021, 09:19
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Let the leap length of dog be D and leap length of cat be C
3 leaps of dog are equal to 5 leaps of cat ,i.e.
3D=5C
So D =5/3C
The dog takes 6 leaps for every 9 leaps of cat, i.e. in the same time say t the dog leaps 6 times and cat leaps 9 times
So distance covered by dog in time t= 6 D = 6*5/3C=10C
Distance covered by cat in same time =9C
So ratio of speed of dog and cat is 10C/9C = 10/9
IM0 B
Posted from my mobile device
3 leaps of dog are equal to 5 leaps of cat ,i.e.
3D=5C
So D =5/3C
The dog takes 6 leaps for every 9 leaps of cat, i.e. in the same time say t the dog leaps 6 times and cat leaps 9 times
So distance covered by dog in time t= 6 D = 6*5/3C=10C
Distance covered by cat in same time =9C
So ratio of speed of dog and cat is 10C/9C = 10/9
IM0 B
Posted from my mobile device
bogano1980
Joined: 12 Aug 2013
Last visit: 28 Sep 2021
Posts: 4
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Location: Georgia
Schools: Goizueta "23
GMAT 1: 650 Q48 V31
GMAT 2: 710 Q49 V37
GPA: 3.87
10 Mar 2021, 09:39
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Dog leaps=6
Cat leaps=9; transform to dog leap\(s=9 leaps* \frac{3}{5} dog leaps=\frac{27}{5} dog leaps.\\
\\
\\
Ratio=\frac{6}{27/5}\)=\(\frac{30}{29}\)=\(\frac{10}{9}\)
Ans: B
Cat leaps=9; transform to dog leap\(s=9 leaps* \frac{3}{5} dog leaps=\frac{27}{5} dog leaps.\\
\\
\\
Ratio=\frac{6}{27/5}\)=\(\frac{30}{29}\)=\(\frac{10}{9}\)
Ans: B
