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Re: A factory has two machines. Machine X can produce 200 pins per hour an [#permalink]
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MathRevolution wrote:
[GMAT math practice question]

A factory has two machines. Machine X can produce 200 pins per hour and machine Y can produce 500 pins per hour. At least one machine is in operation throughout the 8-hour work day. The factory must produce 5,000 pins every day. What is the least possible number of hours that machines X and Y must work together on each day?

A. 4
B. 5
C. 6
D. 7
E. 8


question needs to be understood well before solving as i found it to be a bit confusing;

given ; At least one machine is in operation throughout the 8-hour work day
since we need to find the least together working hours so so let the machine Y with highest rate be in operation for 8 hrs ; it will produce ; 8*500; 4000 pins
left with 5000-4000; 1000 pins ; since contribution of both machines is required so machine x will take ; 1000/200; 5 hrs
now see wording
what is the least possible number of hours that machines X and Y must work together on each day
the least hours worked by both machine will be 5 hrs ; but total hours would be 13 ..
IMO B
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Re: A factory has two machines. Machine X can produce 200 pins per hour an [#permalink]
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=>

In order to minimize the number of hours that the two machines work together, the more efficient machine \(Y\) should work for the entire day.

Thus, \(Y\) works for \(8\) hours and produces \(8 * 500 = 4,000\) pins.

There are \(1,000\) pins remaining for machine \(X\) to produce. This takes \(\frac{1,000}{200} = 5 hours.\)

Therefore, B is the answer.
Answer: B
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Re: A factory has two machines. Machine X can produce 200 pins per hour an [#permalink]
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