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28 Mar 2024, 11:17
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MartyMurray I used the method from TTP.
If the 2 daughters cannot be together I arrange them as 4! - 2!(4-2+1)!
arrange the daughters together, and multiply ways by which the others can be arranged and subtract from 4!
Is this method application wrong?
Posted from my mobile device
If the 2 daughters cannot be together I arrange them as 4! - 2!(4-2+1)!
arrange the daughters together, and multiply ways by which the others can be arranged and subtract from 4!
Is this method application wrong?
Posted from my mobile device
28 Mar 2024, 11:41
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ashdank94
Oh, I think I get it.
I think the issue is that you didn't keep in mind that the two daughers together can be in the back only. So, there are only two positions for the two daugthers together, on the right or the left in the back seats.
So, you can't apply the method normally. You have to take the additional constraint into account.
With that constraint taken into account, the ways the 4 passengers can be arranged is 4! - the arrangements with daugters next to each other.
4! - (2 × 2 × 2) = 24 - 8 =16
28 Mar 2024, 11:45
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Interesting 
it wasn’t specified in the question that daughters have to sit in the back so I assumed it was a shotgun situation lol
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it wasn’t specified in the question that daughters have to sit in the back so I assumed it was a shotgun situation lolPosted from my mobile device
