A function f(n) is defined as 1/n when n is an integer and as 6n when

Question

A function f(n) is defined as 1/n when n is an integer and as 6n when n is a fraction. What is the value of  f(f(f(3^{-2})))  ?

A. 1/4
B. 2/3
C. 3/2
D. 4
E. 9

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BongBideshini · Answer

Looks like a typo, 
f(f(f(3-2)))=f(f(f(1)))=1,
Not in the option

May be 
f(f(f(3-2))) is actually f(f(f(3^{-2})))
=f(f(f(1/9)))
=f(f(6/9))
=f(f(2/3))
=f(12/3)
=f(4)
=1/4

Ans A

Bunuel · Answer

_______________________
Fixed the typo. Thank you!

Adit_ · Answer

f(1/9) = 6/9 = 2/3 
f(2/3) = 4 
f(4) = 1/4.

Answer:  Option A

vasu1104 · Answer

f(n) = 1/n, if n is integer
f(n) = 6n. if n is fraction.

f(f(f(3^-2)))
f(1/3^2) = so n=6n as per stem.
6/9 = 2 /3

now, f(f(2/3))
again n is fraction so f(n) = 6n
6*(2/3)= 4

now, f(4). here n=1/4 since n is an integer.

so ans 1/4

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