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Bunuel
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Bunuel
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AleenBola
If Machine 1 does total work in 24 days and machine B does the same in 30 days. Then the work can be 120 (LCM)
Machine A's rate- 10
Machine B's rate- 8

In one day, 3 shifts, they do a total work of = 27

Hence total number of days taken by them= 4.4

Bunuel. Can you help me with this?
Machine A can complete a certain job in 12 days, working 2 full shifts per day, which means in one shift A does 120/(12*2) = 5 units of work, not 10.

Machine B can complete the same job in 15 days, also working 2 full shifts per day, which means in one shift B does 120/(15*2) = 4 units of work, not 8.

In one day, they work 1.5 shifts each, hence do 7.5 and 6 units of work respectively.

120/(7.5 + 6) = 8.8...

Hope this helps.­
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Working 2 shifts machine A completes the job in 12 days.
Working 2 shifts machine B completes the job in 15 days.
SO if they work just one shift, that means they do only 1/2 the job.

Their original rate for completing 1 job.
A = 1/12
B = 1/15

Now, given that Machine A works during the first shift each day (only 1shift = 1/2 work), Machine B works during the second shift (only 1shift = 1/2 work), and both machines work half of the third shift (1/2 of a shift = 1/2 of 1/2 work = 1/4 work)

We need to find the time to complete the job --> T = W/R

1/2/12 + 1/2/15 + 1/4/12 +1/4/15 = 1/24 + 1/30 + 1/48 + 1/60 = 3/48 + 3/60 = 9/80

= 80/9 = 8.88 (approx. 9 days)
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