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# A gardener is planning a garden layout. There are two rectangular beds

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Re: A gardener is planning a garden layout. There are two rectangular beds [#permalink]
Official Explanation

For Bed A, we’re told that the gardener must include exactly 1 type of shrub and exactly 2 types of annual flower. The problem also specifies that bed A must contain a total of 5 different types of shrubs or flowers, so bed A must also contain 2 types of perennial flower.

To choose 1 shrub from 7 possibilities, we calculate 7!/(1!6!) = 7. When choosing only 1, there is always the same number of possibilities as there is of items (7 possibilities, so 7 choices). To choose 2 annual flowers from 6 possibilities, we calculate 6!/(2!4!) = 15. To choose 2 perennial flowers from 4 possibilities, we calculate 4!/(2!2!) = 6. There are 7 possibilities for a shrub, 15 possibilities for the annual flowers, and 6 possibilities for the perennial flowers. In total, there are 7×15×6 = 630 possibilities for bed A.
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Re: A gardener is planning a garden layout. There are two rectangular beds [#permalink]
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Sajjad1994, It appears that the question is missing in this post. Would be great if you can post the actual question.
Re: A gardener is planning a garden layout. There are two rectangular beds [#permalink]
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