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Sub 505 Level|   Percent and Interest Problems|                        
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Bunuel
A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?

(A) 3.00
(B) 5.00
(C) 5.50
(D) 6.50
(E) 6.75
 

If the concentration is \(15%,\) it means that for every 100 cubic centimeters of solution we have 15 grams of glucose, or for every 100/20 = 5 cubic centimeter we have 15/20 = 3/4 grams of glucose. Therefore, in \(45 = 9\cdot5\) cubic centimeters of solution, we have \(9\cdot\frac{3}{4}=\frac{27}{4}=6.75\) grams of glucose.

Answer E.­
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its 6.75..

how i do it..

i take its Directly proportion or inverse proportion

Glucose 15 solution 100...

glucose X solution 45 ....

45*15/100=6.75


if it wud be inverse relation between them like solution increase and glucose decrease then we wud do like this

15*100/45
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Simple Unitary method :

100cm^3 -------------------------- 15gm
45cm^3 ---------------------------(15/100)*45 = 6.75 (i.e., E)

Cheers :-D
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EvaJager

Bunuel
A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?

(A) 3.00
(B) 5.00
(C) 5.50
(D) 6.50
(E) 6.75

 
If the concentration is \(15%,\) it means that for every 100 cubic centimeters of solution we have 15 grams of glucose, or for every 100/20 = 5 cubic centimeter we have 15/20 = 3/4 grams of glucose. Therefore, in \(45 = 9\cdot5\) cubic centimeters of solution, we have \(9\cdot\frac{3}{4}=\frac{27}{4}=6.75\) grams of glucose.

Answer E.

Nice as usual made by you the right solution :) I like your approach.

A bit straight should be

\(\frac{15}{100}\) \(=\) \(\frac{x}{45}\) -------> 6.75


E wins ­
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Bunuel
A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?

(A) 3.00
(B) 5.00
(C) 5.50
(D) 6.50
(E) 6.75
We are given that a glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. Since we are dealing with a solution, we know that the grams of glucose is proportional to the number of cubic centimeters of solution. Thus, to determine how many grams of glucose would be in the container when we have 45 cubic centimeters of solution, we can set up a proportion.

We can say: “15 grams of glucose is to 100 cubic centimeters of solution as x grams of glucose is to 45 cubic centimeters of solution.” Let’s now set up the proportion and solve for x.

15/100 = x/45

When we cross multiply we obtain:

(15)(45) = 100x

675 = 100x

6.75 = x

There are 6.75 grams of glucose in the solution in the container.

The answer is E.­
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A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?

(A) 3.00
(B) 5.00
(C) 5.50
(D) 6.50
(E) 6.75

15==>100
?==>45

15*45 / 100 = 6.75

45*100 /15 = ?
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Hi All,

This question is ultimately about setting up a ratio. We're told that we have 15 grams of glucose in a 100 cubic cm solution. We're asked how much glucose would be in 45 cubic cm of that solution.

15/100 = X/45

3/20 = X/45

20X = 135

X = 6.75

Final Answer:

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Bunuel
A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 45 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container?

(A) 3.00
(B) 5.00
(C) 5.50
(D) 6.50
(E) 6.75
 
here is mu unique solution of solution :)

15 grams of glucose per 100 cubic --->
\(\frac{15}{100}\) --> \(\frac{3}{20}\)

\(\frac{3}{20}\) *45 = 6.75

is my approach correct? :? :)­
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Glucose per CC= 15/100=0.15gm

for 45cc= 45*0.15= 6.75gm
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