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Plan: to cut 128 trees in d days ---> (128/d) trees a d ay.

First 4 days, 4*(128/d) trees were cut.
Then in the next (d-4-1)=(d-5) days, (d-5)*(128/d+4) trees were cut.

Total trees cut:
4*(128/d)+ (d-5)*(128/d+4) = 164
-(128/d) -20 + 128 +4*d = 164
-128 + 4*d^2 - 56*d = 0
-32 + d^2 - 14*d = 0
(d-16)*(d+2)=0
d=16 days or d=-2 (NA)

The number of trees the group was planning to cut per day = 128/d = 128/16 = 8 trees per day

FINAL ANSWER IS (A)

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A group of people decided to cut 128 trees in a certain number of days. For the first 4 days, they were able to achieve their planned per day target. However, for the remaining days, the group was able to cut 4 more trees daily than planned. In this way, the group had cut 164 trees one day before the planned finish date. What was the number of trees the group was planning to cut per day?

A. 8
B. 12
C. 16
D. 32
E. 64

Method 1:
let the rate of number of trees to cut per day be x
x*d = 128

as they were able to maintain this rate for 4 days, and then increased the rate to (x+4) thereby decreasing the total number of days by one.
x*4 + (x+4)(d-4-1) = 164
x*4 + x*d - x*5 +4*d - 20 = 164
4*d - x = 56
\(4*128 - x^2 = 56x\)
\(4*128 = x( x+ 56)\)
\(8*(8+56) = x( x+ 56)\)
x= 8

Method 2:
    A. 8: initial number of days = 16, 8*4 + 12*11 = 32 + 132 = 164
    B. 12: not possible as it do not divides 128
    C. 16: initial number of days = 8, 16*4 + 20*3 = 64 + 60 = 124 less than the target.
    D. 32: initial number of days = 4, not possible as they worked for 4 days and then some more
    E. 64: initial number of days = 2, not possible as they worked for 4 days and still did not reached their target

Ans: A
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Solution:


Let x be the number of days in which trees are to be cut.
    • Number of trees cut in one day = \(\frac{128}{x}\) trees
    • For the first four days, they cut trees as planned.
      o Trees cut in first 4 days = \(4*\frac{128}{x}\)
    • For the remaining days they cut 4 more trees per day, till one day before the planned day
      o Trees cut in one day = \(\frac{128}{x} + 4\)
      o Now, trees cute in (x-5) days = \((x-5)(\frac{128}{x} + 4)=108 + 4x -5*\frac{128}{x}\)
    • Trees cut in x-1 days = \(4*\frac{128}{x} + 108 +4x -5*\frac{128}{x}\)
    • \(164 = 108 + 4x -\frac{128}{x}\)
    • \(4x^2 -56x – 128 =0\)
    • \(x^2 - 14x – 32 = 0\)
    • \(x^2 – 16x + 2x -32 =0\)
    • \((x-16)(x+2) = 0\)
      o \(x = 16\), we can discard the case of x = -2, because number of days can’t be negative.
    • Number of trees cut per day = \(\frac{128}{16} = 8\).
Hence, the correct answer is Option A
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Quote:
A group of people decided to cut 128 trees in a certain number of days. For the first 4 days, they were able to achieve their planned per day target. However, for the remaining days, the group was able to cut 4 more trees daily than planned. In this way, the group had cut 164 trees one day before the planned finish date. What was the number of trees the group was planning to cut per day?

A. 8
B. 12
C. 16
D. 32
E. 64

rate*time=work, rt=128
(r+4)(t-5)+4r=164
rt-5r+4t-20+4r=164
rt+4t-r=184, (128)+4t-r=184
4t-(128/t)=184-128
4t^2-128=56t, t^2-14t-32=0
(t-16)(t+4)=0, t=16
r(16)=128, r=128/16=8

Ans (A)
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A group of people decided to cut 128 trees in a certain number of days. For the first 4 days, they were able to achieve their planned per day target. However, for the remaining days, the group was able to cut 4 more trees daily than planned. In this way, the group had cut 164 trees one day before the planned finish date. What was the number of trees the group was planning to cut per day?

A. 8
B. 12
C. 16
D. 32
E. 64

x trees per day, n total days as planned
nx = 128
4x+(n-5)(x+4)=164, [sub nx=128, n=128/x]
on solving,
x^2+56x-512=0,
x=8 trees per day.
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A group of people decided to cut 128 trees in a certain number of days. For the first 4 days, they were able to achieve their planned per day target. However, for the remaining days, the group was able to cut 4 more trees daily than planned. In this way, the group had cut 164 trees one day before the planned finish date. What was the number of trees the group was planning to cut per day?

A. 8
B. 12
C. 16
D. 32
E. 64

Let be the number of days the group planned to cut these 128 trees.
Trees cut per day planned = \(\frac{128}{x}\)
Trees cut for first 4 days = \(4*\frac{128}{x}\)
Rest of the days when trees were cut = x - 4 - 1 = x - 5
Trees cut er day for rest of the (x-5) days = \(\frac{128}{x} + 4\)
Now, \(4*\frac{128}{x} + (x-5)*(\frac{128}{x} + 4) = 164\)
\(x^2 - 14x - 32 = 0\)
x = 16
Trees cut per day planned = \(\frac{128}{x} =\frac{128}{16} = 8\)

Answer A.
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Let original days required be D and Trees cut per day be T

A group of people decided to cut 128 trees in a certain number of days.

This means \(D * T = 128\) --- (1)

For the first 4 days, they were able to achieve their planned per day target. However, for the remaining days, the group was able to cut 4 more trees daily than planned. In this way, the group had cut 164 trees one day before the planned finish date.

This makes the below equation -

\((4 * T) + (D - 4 - 1) (T + 4) = 164\)
\(4T + (D-5)(T+4) = 164\)
\(4T + DT - 5T + 4D - 20 = 164\)
\(4D + DT = 184 + T\) --- (2)

From (1) and (2), we get
\(4D + 128 = 184 + T\)
\(4D = 56 + T\) --- (3)

Now we need what was the number of trees the group was planning to cut per day, that is 'T'

Substituting D from (1) in (3);

\(\frac{128}{T}*4 = 56 + T\)
\(T^2 + 56T - 512 = 0\)

Solving for T,

\(T^2 + 64T - 8T - 512 = 0\)
\((T - 8)(T + 64) = 0\)

Hence T = 8, (A)
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Pretty fast way of solving -

Let the number of days be - n
Let the number of trees cut per day - x

x*n = 128 -(1)

4x + (n-4-1)(x+4) = 168 -(2)

From (1) and (2),

4x + (128/x - 5)(x + 4) = 168

Now as solving this equation can get cumbersome we start putting the options into it,

(d) and (e) can be eliminated

=> (128/x - 5)<0

=> Putting (a),(b),(c),

We find that option (a) satisfies

Answer - (a)
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