gmatbusters wrote:
A large urn contains 100 balls, of which 36% are red and the rest are blue. How many of the blue balls must be removed so that the percentage of red balls in the urn will be 72% (No red balls are to be removed.)
A) 28
B) 32
C) 36
D) 50
E) 64
This took me ~2 mins to understand the question ..
From given info total balls =100, out of which red 36 and blue 64
We have to find total of balls which would make the count of 36 red balls as 72% of the total which has to be done by removal of blue balls.
So lets find value of total balls at which 36 red balls is 72%
Let x be total balls
36/x= 0.72
solve of x we get 50 , since given that total balls are 100 and we have found that @ 50 , 36 red balls would be 72% so we would have to remove 50 out of 64 available blue balls to make the red balls @ 72%, IMO D..
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