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If starting digit be 0, then it will be five digit/letter instead of 6 ... Am I missing something Bunuel?
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If starting digit be 0, then it will be five digit/letter instead of 6 ... Am I missing something Bunuel?

We are not talking about 6-digit number, we are talking about 6-digit license plate, which can start with 0.
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Apply the fundamental counting principle.

Since there are no restrictions, there are 36 possible choices for each spot.

36^6

Answer is A.
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Hi,

I am having a little trouble understanding the solution 36^6. Wouldn't this mean that 2 different license plates can be exactly the same, i.e. one can be "111111" and another can also be "111111", because ways of choosing either was 36^6?

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Hi Shivam,

Since the prompt does not state that there are any restrictions on 'where' a number or letter can be placed, we have to assume that each number and each letter can appear anywhere and can also be used more than once.

So, the first few license plates would be...
000000
000001
000002
000003
Etc.

And the last few license plates would be...
ZZZZZZ
ZZZZZY
ZZZZZX
Etc.

In this way, each of the 6 "spots" on the license plate could hold ANY of the 36 options (the 10 digits and 26 letters) and placing a number or letter in a 'spot' has NO effect on what can be placed in the other 'spots.' This means that we have:

(36)(36)(36)(36)(36)(36) = 36^6 possible license plates.

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