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A man is a climbing up a 100-foot high mountain. Each day he climbs 30

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Bunuel
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A man is a climbing up a 100-foot high mountain. Each day he climbs 30 [#permalink] New post   10 Apr 2017, 02:23
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A man is a climbing up a 100-foot high mountain. Each day he climbs 30 feet but then falls 20 feet. How long does it take him to reach the top assuming that once he reaches the top he does not fall?

A. 7
B. 8
C. 9
D. 10
E. 11
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Re: A man is a climbing up a 100-foot high mountain. Each day he climbs 30 [#permalink] New post   10 Apr 2017, 03:58
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I started by considering that in the last day he will climb 30ft without falling back, which means that if he arrives at 70ft than it will take one more day to reach the top.
Hence, since he climbs at a "net" ratio of 10ft/day, it will take him 7 days to reach the 70ft mark, and one more day to reach the top. Therefore, it'll take him 8 days to reach the top.
So, IMO the answer should be B.
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Re: A man is a climbing up a 100-foot high mountain. Each day he climbs 30 [#permalink] New post   10 Apr 2017, 11:56
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Bunuel wrote:
A man is a climbing up a 100-foot high mountain. Each day he climbs 30 feet but then falls 20 feet. How long does it take him to reach the top assuming that once he reaches the top he does not fall?

A. 7
B. 8
C. 9
D. 10
E. 11


Day 1 = 30 ft - 20 ft = 10 ft rise
Day 2 = 40 ft - 20 ft = 20 ft rise
Day 3 = 50 ft - 20 ft = 30 ft rise
Day 4 = 60 ft - 20 ft = 40 ft rise
Day 5 = 70 ft - 20 ft = 50 ft rise
Day 6 = 80 ft - 20 ft = 60 ft rise
Day 7 = 90 ft - 20 ft = 70 ft rise
Day 8 = 100 ft

Thus, the man will reach 100 ft mountain in 8th day....

Hence, answer will be (B) 8th day..
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Re: A man is a climbing up a 100-foot high mountain. Each day he climbs 30 [#permalink] New post   10 Apr 2017, 19:22
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Bunuel wrote:
A man is a climbing up a 100-foot high mountain. Each day he climbs 30 feet but then falls 20 feet. How long does it take him to reach the top assuming that once he reaches the top he does not fall?

A. 7
B. 8
C. 9
D. 10
E. 11


Net rise in height climbed in 1 days = 30-20 = 10 feet

Hence, man will attain height of 70 in = 7 days

Remaining 30 feet will be climbed by man in just 1 days

So total days to rise 100 feet = 7+1 = 8 days

Answer: Option B
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Re: A man is a climbing up a 100-foot high mountain. Each day he climbs 30 [#permalink] New post   13 Mar 2018, 17:06
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Bunuel wrote:
A man is a climbing up a 100-foot high mountain. Each day he climbs 30 feet but then falls 20 feet. How long does it take him to reach the top assuming that once he reaches the top he does not fall?

A. 7
B. 8
C. 9
D. 10
E. 11


Notice that on the last day, he will not fall. So on the last day he will climb 30 feet, which means he has 70 feet to climb before the last day. For those 70 feet, each day the man climbs a net distance of 30 - 20 = 10 feet, so it will take 70/10 = 7 days to climb those 70 feet. Since he needs one more day to climb the last 30 feet, he needs a total of 8 days to climb to the top.

Answer: B
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Re: A man is a climbing up a 100-foot high mountain. Each day he climbs 30 [#permalink]
13 Mar 2018, 17:06
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