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28 Jul 2010, 08:20
7
8
00:00

Difficulty:

55% (hard)

Question Stats:

64% (01:55) correct 36% (02:57) wrong based on 226 sessions

### HideShow timer Statistics

A man sold 20 articles for $60 and gained 20%. How many articles should he sell for$90 to incur a loss 20%?

A. 45
B. 36
C. 40
D. 50
E. 48

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Joined: 02 Apr 2010
Posts: 100

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28 Jul 2010, 08:35
Production cost per article: $60*(100%-20%) / 20 =$2.40

Required production costs for a loss of 20%: $90*(100% + 20%) =$108

If a selling price of $90 for y articles makes a 20% loss then production price for those y articles is 90/.08 = 112.5 Since each article costs 2.5, y*2.5 =112.5 ==> y=45 _________________ ___________________________________ Please give me kudos if you like my post Manager Joined: 16 Mar 2010 Posts: 143 Re: Another percent problem [#permalink] ### Show Tags 28 Jul 2010, 19:25 Please help me here... I get the answer 50. OA is definately correct or am i making some mistake please correct me where i am wrong. 20 articles for$60 means selling price = 3
20% profit is made so Cost Price = 2.5

Man has to incur a loss of 20% means he has to make a total loss of 20% and he sells X units in 90$60+90 = 0.8 * (C.P. for 20+X units) C.P. for 20+X units = 75*5/2 But the cost price for one unit is 2.5 so, 75*5/(2*2.5) = 75 = Number of units sold. 20 units were sold for 60$ so 55 units sold for 90$Can someone explain where am i wrong here??? Manager Joined: 20 Mar 2010 Posts: 78 Re: Another percent problem [#permalink] ### Show Tags 28 Jul 2010, 20:33 amitjash wrote: Please help me here... I get the answer 50. OA is definately correct or am i making some mistake please correct me where i am wrong. 20 articles for$60 means selling price = 3
20% profit is made so Cost Price = 2.5

Man has to incur a loss of 20% means he has to make a total loss of 20% and he sells X units in 90$60+90 = 0.8 * (C.P. for 20+X units) C.P. for 20+X units = 75*5/2 But the cost price for one unit is 2.5 so, 75*5/(2*2.5) = 75 = Number of units sold. 20 units were sold for 60$ so 55 units sold for 90$Can someone explain where am i wrong here??? The loss of 20% in the second part of the question doesn't include the initial 20 items. It's just on the X number of items he needs to sell for a total of$90.
So 90=0.8(C.P of x units) So C.P of x units=$112.5 and since we know that C.P of each item is$2.5.
No of items he need to sell or x= 112.5/2.5 =45
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Concentration: Finance

### Show Tags

16 Jan 2014, 21:01
c=cost per item
q=quantity of items

20%gain
60/20c=1.2
c=3/1.2

20%loss
90/(3/1.2)*q=.8
90=(2.4/1.2)q
q=45
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Re: A man sold 20 articles for $60 and gained 20%. How many [#permalink] ### Show Tags 27 Jan 2015, 21:14 2 Cost price of 20 articles $$= 100 * \frac{60}{120} = 50$$ Cost price per article $$= \frac{50}{20}$$ To make a 20% loss, selling price per article $$= 80 * \frac{50}{20} * \frac{1}{100} = 2$$ Number of articles for$90 loss $$= \frac{90}{2} = 45$$

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Intern
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Posts: 24
Re: A man sold 20 articles for $60 and gained 20%. How many [#permalink] ### Show Tags 06 Feb 2015, 21:59 CP of 20 items = 50 CP of 1 item = 2.5 To sell one item at 20% loss , SP of 1 item = 2.5*8/100 = 2 We need to sell 45 items to have a SP of$90.

SP = 45
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WE: General Management (Transportation)

### Show Tags

14 Oct 2016, 00:20
USE Percentage method:-

man sells 20 articles for 60 so per article selling price is 3 dollars-

gain is 20 above the regular price- which is 100+20=120 percent for 3 dollars

so

if for 3 dollars ---->120 percent

for x dollars -------> 80 percent (20% loss =regular price - 20%=100-20=80 %)
we will get x=2

GIVEN selling price to get 20% loss is 90 dollars
now 90/2=45 (A)
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Posts: 358
Location: Germany
Concentration: General Management, Finance
GPA: 3.6
WE: Analyst (Transportation)

### Show Tags

02 Dec 2018, 07:05
rxs0005 wrote:
A man sold 20 articles for $60 and gained 20%. How many articles should he sell for$90 to incur a loss 20%?

A. 45
B. 36
C. 40
D. 50
E. 48

Lets say each article costed him x and he initially sold them for 1.2x (Because he sold for 20% profit).

so 20 * 1.2x = 60 => x = 2.5.

Cost price for article = 2.5. If it were to 20 % loss, selling price should be 80% of cost price, Selling price = 0.8 * 2.5 = 2

if he sold each item for $2, he must sell 90/2 items , that are 45 items. Hence answer is A Intern Joined: 10 Sep 2018 Posts: 45 Re: A man sold 20 articles for$60 and gained 20%. How many  [#permalink]

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02 Dec 2018, 10:10
ok So
here are my two cents

Profit % is given so

20= ((SP-CP)/CP)* 100

20= (( 60*20 - x)/x) *100

Solving for x we get x=1000 i.e cost of 20 items is 1000

Now he is selling some articles at 90 $and the loss % is given as 20 CP is fixed at 1000 Loss% =( (CP-SP)/CP)*100 20 = ((1000- 90 *N)/1000)*100 solving for N i get N = 80/9 and i am nowhere near any of the options so what did i do wrong here Please explain Director Joined: 31 Oct 2013 Posts: 876 Concentration: Accounting, Finance GPA: 3.68 WE: Analyst (Accounting) Re: A man sold 20 articles for$60 and gained 20%. How many  [#permalink]

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02 Dec 2018, 12:31
rxs0005 wrote:
A man sold 20 articles for $60 and gained 20%. How many articles should he sell for$90 to incur a loss 20%?

A. 45
B. 36
C. 40
D. 50
E. 48

Sp of an article = 3

cp = 3/120 * 100 = 5/2

we want to incur loss of 20% . sp must be 80 of 5/2.

(5/2 )* 80/100 = 2.

total sp : 90

selling price : 2

90/2 = 45.

The correct answer must be A.