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# A man whose bowling average is 12.4 takes 5 wickets for 26 runs and th

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Math Expert
Joined: 02 Sep 2009
Posts: 58446
A man whose bowling average is 12.4 takes 5 wickets for 26 runs and th  [#permalink]

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21 Feb 2019, 00:44
00:00

Difficulty:

45% (medium)

Question Stats:

63% (02:14) correct 38% (02:22) wrong based on 16 sessions

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A man whose bowling average is 12.4 takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number of wickets taken by him before his last match is:

A. 85
B. 78
C. 72
D. 64
E. 62

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Re: A man whose bowling average is 12.4 takes 5 wickets for 26 runs and th  [#permalink]

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21 Feb 2019, 03:45
Bunuel wrote:
A man whose bowling average is 12.4 takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number of wickets taken by him before his last match is:

A. 85
B. 78
C. 72
D. 64
E. 62

Bowling average = Runs / wicket

Old Average = 12.4

New inning = 26/5 = 5.2

new average = (12.4*x+26) / (x+5) = 12

i.e. 12x + 60 = 12.4x + 26

i.e. 0.4x = 34

i.e. x = 85

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Re: A man whose bowling average is 12.4 takes 5 wickets for 26 runs and th  [#permalink]

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21 Feb 2019, 10:22
Bunuel wrote:
A man whose bowling average is 12.4 takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number of wickets taken by him before his last match is:

A. 85
B. 78
C. 72
D. 64
E. 62

avg ; 26/5 ; 5.2
12.4*x+26= 12* (x+5)

x = 85
IMO A
Re: A man whose bowling average is 12.4 takes 5 wickets for 26 runs and th   [#permalink] 21 Feb 2019, 10:22
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