A milkman sells milk after adding some water in it. Quantity

Solution:

Since the answer options are in percentage, we can take numbers and work to get our asnwer.

Let us assume the milkman bought \(100\) liters of milk in \($100\) (His Cost Price)

Now we know that the quantity of water is \(74\)% of the quantity of milk in the mixture. This means that in this \(100\) liters of milk, he added \(\frac{74}{100}\times 100=74\) liters of water.

So the total mixture \(= 100+74=174\) liters

Now ideally he should sell this \(174\) liters mixture in \($174\). But he gives a \(16.66\)% discount.

So, the Selling Price (SP) \(= 174-(\frac{16.66}{100}\times 174)=174-(\frac{1}{6}\times 174)=174-29=145\)

Thus, the milkman bought milk for \($100\) and sold it for \($145\). Hence profit \(= 145-100=45\).

Profit percent \(= \frac{45}{100}\times 100=45\)%

Hence the right answer is Option C.