ShankSouljaBoi wrote:
Correct in 1 way. Not correct in two ways.
CCCCNNN
= 7!/4!3! = 35.
Since each not correct can have two possibilities ----> total favourable = 2*2*2*35 = 280
Total outcomes = 3*3*3*3*3*3*3 = 3^7
D
Great explanation, just to tweak a little
desired outcome CCCCWWW :
the probability for correct answer is \(\frac{1}{3}\) and same for wrong answer is \(\frac{2}{3}\)
we can directly write P(CCCCWWW)= \(\frac{7!}{4!3!}*\frac{1}{3}*\frac{1}{3}*\frac{1}{3}*\frac{1}{3}*\frac{2}{3}*\frac{2}{3}*\frac{2}{3}\) = \(\frac{280}{3^7}\)
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