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A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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30 Sep 2016, 06:20

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A

B

C

D

E

Difficulty:

65% (hard)

Question Stats:

51% (01:32) correct
49% (01:06) wrong based on 165 sessions

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A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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30 Sep 2016, 07:27

1

This post received KUDOS

duahsolo wrote:

A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A) 30 B) 40 C) 50 D) 120 E) 160

Hi vp101 & abhimahna,

I can confirm that the OA is correct.

Now to the question:

Let's say the amount of grape juice to be added to increase the percentage of grape juice in the container to 20% is x

ORIGINAL %age of grape juice in the container = 120/800 = 15%

NEW %age of grape juice in the container = (120 + x) / ( 800 + x) = 20% ------> 600 + 5x = 800 + x -----> x = 50

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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30 Sep 2016, 07:31

1

This post received KUDOS

duahsolo wrote:

duahsolo wrote:

A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A) 30 B) 40 C) 50 D) 120 E) 160

Hi vp101 & abhimahna,

I can confirm that the OA is correct.

Now to the question:

Let's say the amount of grape juice to be added to increase the percentage of grape juice in the container to 20% is x

ORIGINAL %age of grape juice in the container = 120/800 = 15%

NEW %age of grape juice in the container = (120 + x) / ( 800 + x) = 20% ------> 600 + 5x = 800 + x -----> x = 50

Answer is C (50)

Ohh, I missed such a simple point. Anyways, thanks.
_________________

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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30 Sep 2016, 09:04

1

This post was BOOKMARKED

duahsolo wrote:

A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A) 30 B) 40 C) 50 D) 120 E) 160

Quote:

The test container of 800 milliliters is 15% grape juice.

Grape Juice = 120 ml Water = 680 ml Total Solution = 800 ml

Quote:

If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added

So, \(\frac{(120 + k )}{( 800 + k )}= \frac{20}{100}\)

Or, \(\frac{(120 + k )}{( 800 + k )}= \frac{1}{5}\)

Or, \(600 + 5k = 800 + k\)

Or, \(4k = 200\)

Or, \(k = 50\) So, 50 ml of Grape juice , must be added , answer must be (C) _________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

Is it possible to do this using weighted avg? I tried after reading your post on 'weighted avg and mixture problems on GMAT' but cant seem to make it work. Is weighted avg used only when the same solution is considered and not two separate like in this case?
_________________

If you analyze enough data, you can predict the future.....its calculating probability, nothing more!

Is it possible to do this using weighted avg? I tried after reading your post on 'weighted avg and mixture problems on GMAT' but cant seem to make it work. Is weighted avg used only when the same solution is considered and not two separate like in this case?

Aaahhhhhh I think I got it, please correct me if I am wrong:

Initial grape juice percent = 15% = \(\frac{5}{20}\) 100% concentration grape juice = 1 Grape juice concentration in final mixture = 20% = \(\frac{1}{5}\)

A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

Show Tags

02 Oct 2016, 21:58

15% of 800ml means we've got 120 ml of grape juice.

Hmmm... looking at the answer choices we've got some easy well rounded numbers, perfect for plugging in answers. Let's do that.

Starting with B, we add 40ml and have 840ml total, 20% of that is 168ml of grape juice. BUT 120ml of original grape juice plus the 40ml we just added comes out to 160ml (not equal to 168ml). So B doesnt work (it's too low).

Let's try the same thing with answer choice D. We add 120ml of juice to get 920ml total. 20% of that is 184ml, 120ml of original grape juice plus the 120ml we just added comes out to 240ml (not equal to 184ml). So D doesnt work (it's too high).

Is it possible to do this using weighted avg? I tried after reading your post on 'weighted avg and mixture problems on GMAT' but cant seem to make it work. Is weighted avg used only when the same solution is considered and not two separate like in this case?

Aaahhhhhh I think I got it, please correct me if I am wrong:

Initial grape juice percent = 15% = \(\frac{5}{20}\) 100% concentration grape juice = 1 Grape juice concentration in final mixture = 20% = \(\frac{1}{5}\)

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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20 Oct 2016, 06:50

Is it possible to do this using weighted avg? I tried after reading your post on 'weighted avg and mixture problems on GMAT' but cant seem to make it work. Is weighted avg used only when the same solution is considered and not two separate like in this case?[/quote]

Aaahhhhhh I think I got it, please correct me if I am wrong:

Initial grape juice percent = 15% = \(\frac{5}{20}\) 100% concentration grape juice = 1 Grape juice concentration in final mixture = 20% = \(\frac{1}{5}\)

Yes, correct! Though I would use percentages only. They are easier to manipulate compared with fractions.

800/w2 = (100 - 20)/(20 - 15) = 16/1

w2 = 50[/quote]

Hi VeritasPrepKarishma,

I had tried using the weighted average formula but could not do so. I see that you have performed the following:

Comparing the step 800/w2 = (100 - 20)/(20 - 15) = 16/1 to the weighted average formula, i don't seem to figure why we have taken 100 % here.

n1/n2=(A2-Aw)/(Aw-A1). So Aw here is 20, A1 is 15, n1 is 800. How did you take A2 as 100? What is the logic behind it? Can you please explain it to me?

A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

Show Tags

20 Oct 2016, 16:04

vrgmat wrote:

Is it possible to do this using weighted avg? I tried after reading your post on 'weighted avg and mixture problems on GMAT' but cant seem to make it work. Is weighted avg used only when the same solution is considered and not two separate like in this case?

Aaahhhhhh I think I got it, please correct me if I am wrong:

Initial grape juice percent = 15% = \(\frac{5}{20}\) 100% concentration grape juice = 1 Grape juice concentration in final mixture = 20% = \(\frac{1}{5}\)

Yes, correct! Though I would use percentages only. They are easier to manipulate compared with fractions.

800/w2 = (100 - 20)/(20 - 15) = 16/1

w2 = 50[/quote]

Hi VeritasPrepKarishma,

I had tried using the weighted average formula but could not do so. I see that you have performed the following:

Comparing the step 800/w2 = (100 - 20)/(20 - 15) = 16/1 to the weighted average formula, i don't seem to figure why we have taken 100 % here.

n1/n2=(A2-Aw)/(Aw-A1). So Aw here is 20, A1 is 15, n1 is 800. How did you take A2 as 100? What is the logic behind it? Can you please explain it to me?[/quote]

Initial concentration of grape juice is 15% and we are asked to increase the percentage of grape juice to 20%. The only way to do this is by adding a certain amount of 100% grape juice and that is where the 100% comes from. _________________

If you analyze enough data, you can predict the future.....its calculating probability, nothing more!

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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20 Oct 2016, 23:35

colorblind wrote:

vrgmat wrote:

Is it possible to do this using weighted avg? I tried after reading your post on 'weighted avg and mixture problems on GMAT' but cant seem to make it work. Is weighted avg used only when the same solution is considered and not two separate like in this case?

Aaahhhhhh I think I got it, please correct me if I am wrong:

Initial grape juice percent = 15% = \(\frac{5}{20}\) 100% concentration grape juice = 1 Grape juice concentration in final mixture = 20% = \(\frac{1}{5}\)

Yes, correct! Though I would use percentages only. They are easier to manipulate compared with fractions.

800/w2 = (100 - 20)/(20 - 15) = 16/1

w2 = 50[/quote]

Hi VeritasPrepKarishma,

I had tried using the weighted average formula but could not do so. I see that you have performed the following:

Comparing the step 800/w2 = (100 - 20)/(20 - 15) = 16/1 to the weighted average formula, i don't seem to figure why we have taken 100 % here.

n1/n2=(A2-Aw)/(Aw-A1). So Aw here is 20, A1 is 15, n1 is 800. How did you take A2 as 100? What is the logic behind it? Can you please explain it to me?[/quote]

Initial concentration of grape juice is 15% and we are asked to increase the percentage of grape juice to 20%. The only way to do this is by adding a certain amount of 100% grape juice and that is where the 100% comes from.[/quote]

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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10 Mar 2017, 13:53

duahsolo wrote:

A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A) 30 B) 40 C) 50 D) 120 E) 160

Hi there, I don't understand why we are using the formula 120+x/800+x to arrive at the answer. The question stem has asked "how much grape juice to be added in the container"? Since the container's capacity is 800 ml we cannot use 800+x as the juice will spill out. @Experts: your thoughts please?

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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10 Mar 2017, 17:31

duahsolo wrote:

A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A) 30 B) 40 C) 50 D) 120 E) 160

let x=ml of grape juice to be added .15*800+x=.2(800+x) x=50 ml C

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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11 Mar 2017, 11:34

rt9 wrote:

this is poorly worded. if the test container is of 800ml, why should i assume that it can hold 850ml??

The exact same assumption stumped me too. I interpreted the container to be of 800 ml Volume. Now to me, "response", meant that someone would suck out some volume of liquid from the 800 ml filled container resulting in reduction of the liquid Now one has to add some X ml of Grape juice to make it back to 800 ml mixture Hence I computed (120 + X)/800= 0.2 resulting in X= 40

Re: A new beverage, which is a mixture of grape juice and apple juice, is [#permalink]

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04 Sep 2017, 21:10

I will better use options here, 15% of 800 = 120 So adding grape juice from options Starting with option C: Option C: Total grape = 120+50= 170 Total Juice = 800+50=850 20% of 850 = 170 Thus option C _________________

Abhishek Parikh Math Tutor Whatsapp- +919983944321 Mobile- +971529685639 Website: http://www.holamaven.com

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