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A new beverage, which is a mixture of grape juice and apple juice, is

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A new beverage, which is a mixture of grape juice and apple juice, is  [#permalink]

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New post 19 Mar 2017, 07:12
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Question Stats:

61% (01:26) correct 39% (01:12) wrong based on 219 sessions

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A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A. 30
B. 40
C. 50
D. 120
E. 160

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Re: A new beverage, which is a mixture of grape juice and apple juice, is  [#permalink]

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New post 19 Mar 2017, 14:55
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In the original Test Container of 800 milliliters, grape juice is 15%, i.e. 120 milliliters

To make the grape juice % to 20%, let the amount of grape juice added = x milliliters

(120+x)/(800+x) = 0.2

Solving for X gives as x = 50

Answer is C. 50
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Re: A new beverage, which is a mixture of grape juice and apple juice, is  [#permalink]

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New post 19 Mar 2017, 19:15
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Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A. 30
B. 40
C. 50
D. 120
E. 160



Initial volume of grape juice in beverage 15% of 800 = 120ML
let X amount be added then
this new volume will represent 20% of final volume
120+x = 20% of (800+x)
solving X =50 ML

Ans C
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Re: A new beverage, which is a mixture of grape juice and apple juice, is  [#permalink]

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New post 20 Mar 2017, 01:20
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A. 30
B. 40
C. 50
D. 120
E. 160

let the grape juice added be x
apple juice in initial mixture = 0.85*800
apple juice in final mixture = 0.8(800 +x)
since the apple juice in both the mixture is same, therefore
0.85*800 = 0.8(800+ x)
0.05*800 = 0.8x
or x= 0.05*800/0.8 = 50ml

Option C
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Re: A new beverage, which is a mixture of grape juice and apple juice, is  [#permalink]

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New post 24 Mar 2017, 18:30
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Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A. 30
B. 40
C. 50
D. 120
E. 160


800 ml, 15% grape juice = 120ml grape & 85% apple = 680.

Now 680 must be 80% of new mixture so find value that 680ml is 80% of. so (680/8)*10 = 850 hence 50 more.
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Re: A new beverage, which is a mixture of grape juice and apple juice, is  [#permalink]

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New post 24 Mar 2017, 19:35
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A. 30
B. 40
C. 50
D. 120
E. 160


let x=ml of grape juice to be added
.15*800+x=.2(800+x)
x=50 ml
C
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Re: A new beverage, which is a mixture of grape juice and apple juice, is  [#permalink]

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New post 31 May 2018, 16:09
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A. 30
B. 40
C. 50
D. 120
E. 160


Initially there is 800 x 0.15 = 120 ml of grape juice and thus 680 ml of apples juice. We can let g = the amount of grape juice to be added and create the equation:

(120 + g)/(800 + g) = 1/5

5(120 + g) = 800 + g

600 + 5g = 800 + g

4g = 200

g = 50

Alternate Solution:

To 800 ml of 15% grape juice, we add x ml of 100% grape juice to obtain (800 + x) ml of 20% grape juice. Converting the percentages to decimals, we can create the equation:

800(0.15) + x(1.0) = (800 + x)(0.20)

120 + x = 160 + 0.20x

0.8x = 40

8x = 400

x = 50

Answer: C
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Re: A new beverage, which is a mixture of grape juice and apple juice, is  [#permalink]

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New post 23 Jun 2018, 08:05
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?

A. 30
B. 40
C. 50
D. 120
E. 160




let x ml of grape juice(100 % grapes juice mixture) is required to be added to make the final % of grape juice to be 20 %

therefore
800/x = (100 - 20)/(20-15)

x = 800/16 = 50 %
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Re: A new beverage, which is a mixture of grape juice and apple juice, is &nbs [#permalink] 23 Jun 2018, 08:05
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