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A new beverage, which is a mixture of grape juice and apple juice, is
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19 Mar 2017, 07:12
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Difficulty:
45% (medium)
Question Stats:
61% (01:26) correct 39% (01:12) wrong based on 219 sessions
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A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?
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19 Mar 2017, 19:15
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Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?
A. 30 B. 40 C. 50 D. 120 E. 160
Initial volume of grape juice in beverage 15% of 800 = 120ML let X amount be added then this new volume will represent 20% of final volume 120+x = 20% of (800+x) solving X =50 ML
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20 Mar 2017, 01:20
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?
A. 30 B. 40 C. 50 D. 120 E. 160
let the grape juice added be x apple juice in initial mixture = 0.85*800 apple juice in final mixture = 0.8(800 +x) since the apple juice in both the mixture is same, therefore 0.85*800 = 0.8(800+ x) 0.05*800 = 0.8x or x= 0.05*800/0.8 = 50ml
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24 Mar 2017, 18:30
1
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?
A. 30 B. 40 C. 50 D. 120 E. 160
800 ml, 15% grape juice = 120ml grape & 85% apple = 680.
Now 680 must be 80% of new mixture so find value that 680ml is 80% of. so (680/8)*10 = 850 hence 50 more.
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24 Mar 2017, 19:35
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?
A. 30 B. 40 C. 50 D. 120 E. 160
let x=ml of grape juice to be added .15*800+x=.2(800+x) x=50 ml C
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31 May 2018, 16:09
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?
A. 30 B. 40 C. 50 D. 120 E. 160
Initially there is 800 x 0.15 = 120 ml of grape juice and thus 680 ml of apples juice. We can let g = the amount of grape juice to be added and create the equation:
(120 + g)/(800 + g) = 1/5
5(120 + g) = 800 + g
600 + 5g = 800 + g
4g = 200
g = 50
Alternate Solution:
To 800 ml of 15% grape juice, we add x ml of 100% grape juice to obtain (800 + x) ml of 20% grape juice. Converting the percentages to decimals, we can create the equation:
800(0.15) + x(1.0) = (800 + x)(0.20)
120 + x = 160 + 0.20x
0.8x = 40
8x = 400
x = 50
Answer: C
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Jeffery Miller Head of GMAT Instruction
GMAT Quant Self-Study Course 500+ lessons 3000+ practice problems 800+ HD solutions
Re: A new beverage, which is a mixture of grape juice and apple juice, is
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23 Jun 2018, 08:05
Bunuel wrote:
A new beverage, which is a mixture of grape juice and apple juice, is being tested. The test container of 800 milliliters is 15% grape juice. If the response to the beverage causes the maker to increase the percentage of grape juice in the container to 20%, how much grape juice will be added?
A. 30 B. 40 C. 50 D. 120 E. 160
let x ml of grape juice(100 % grapes juice mixture) is required to be added to make the final % of grape juice to be 20 %
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61% (01:26) correct 
