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# A painting 4.5 ft X 1.4 ft is to be bordered with a 3 inches wide wood

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Manager
Joined: 26 Nov 2018
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Concentration: Technology, Entrepreneurship
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A painting 4.5 ft X 1.4 ft is to be bordered with a 3 inches wide wood  [#permalink]

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04 Mar 2019, 07:30
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Difficulty:

95% (hard)

Question Stats:

20% (03:05) correct 80% (02:25) wrong based on 49 sessions

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A painting 4.5 ft X 1.4 ft is to be bordered with a 3 inches wide wooden strip. What is the minimum length of the strip required to border the painting?

A. 13
B. 14
C. 15
D. 16
E. 17
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Affiliations: CrackVerbal
Joined: 03 Oct 2013
Posts: 563
Location: India
GMAT 1: 780 Q51 V46
Re: A painting 4.5 ft X 1.4 ft is to be bordered with a 3 inches wide wood  [#permalink]

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06 Mar 2019, 03:36
1
Top Contributor
Hello,

Greetings for the day.

Although this question looks like a simple question on mensuration, there is a trick element involved in it, and therefore, it is very easy to make calculation mistakes.

We are required to find the length of the strip required to border the painting.
The dimensions of the painting are 4.5 feet by 1.4 feet. This is a rectangle.
If we draw a border of 3 inches width, we will obtain a rectangle which is both longer and wider, around the painting. Because we have to calculate the length of this border, essentially, we are required to calculate the perimeter of the outer rectangle.

Also, since the width of the border is given in inches, whereas the dimensions of the painting are given in feet, it’s a good idea to convert feet to inches.

1 foot = 12 inches.

Therefore, 4.5 feet = 4 feet + 0.5 feet = 48 + 6 = 54 inches
and 1.4 feet = 1 feet + 0.4 feet = 12 + 4.8 = 16.8 inches

The whole situation above can be represented as shown in the diagram below.

Attachment:

GMAT Club - 05032019.jpg [ 33.53 KiB | Viewed 583 times ]

We can see from the figure that the length of the outer rectangle is 60 inches and the width of the outer rectangle is 22.8 inches.
Hence, the minimum length of the border has to be 60 inches and the minimum width has to be 22.8 inches.
Now, 60 inches = 5 feet and 1feet< 22.8 inches < 2 feet.
Since all the options are given in terms of integers, the minimum width of the border has to be 24 inches I.e. 2 feet. Therefore, the minimum perimeter of the outer rectangle will have to be 2(60 + 24) = 168 inches which is nothing but 14 feet.

There we go, the correct answer option is B.

A point to be noted here is the importance of being good at conversions. If you are well versed with the basic conversions, then you will be in a great position to convert this question from a tricky question to an easy question.

Hope this helps!
Cheers.
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Re: A painting 4.5 ft X 1.4 ft is to be bordered with a 3 inches wide wood  [#permalink]

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12 Apr 2019, 03:09
this question is not good , first of all I don't know 1 ft = how much inches , am I supposed to meomrize that ?
secondly , you are asking for the minimum length of the stripe , what is the unit ? how are we supposed to assume that you want the length in inches , or in feet !?
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Re: A painting 4.5 ft X 1.4 ft is to be bordered with a 3 inches wide wood  [#permalink]

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06 May 2019, 11:24
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Joined: 10 Apr 2019
Posts: 1
Re: A painting 4.5 ft X 1.4 ft is to be bordered with a 3 inches wide wood  [#permalink]

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06 May 2019, 15:05
2
I believe the correct answer isA (13). The question specified “a strip”. Home Depot sells 3 inch strips in lengths as long as 20 feet.
You need 5 feet for the top (4.5+.25+.25), 5 feet for the bottom, 1.4 feet on the right side and 1.4 feet on the left side. That sums to 12.8 which rounds up to 13. Thanks to your miter saw, you can make excellent square cuts. If you wanted 45° cuts, the question should’ve been more clear!
Please correct me where I am wrong.
Craig1954

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Craig1954
Re: A painting 4.5 ft X 1.4 ft is to be bordered with a 3 inches wide wood   [#permalink] 06 May 2019, 15:05
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