Last visit was: 21 Apr 2026, 14:04 It is currently 21 Apr 2026, 14:04
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
505-555 (Easy)|   Percent and Interest Problems|   Word Problems|                     
User avatar
SimaQ
Joined: 06 Feb 2006
Last visit: 24 May 2007
Posts: 430
Own Kudos:
649
 [96]
Posts: 430
Kudos: 649
 [96]
10
Kudos
Add Kudos
86
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
viks4gmat
Joined: 04 Jun 2011
Last visit: 20 Apr 2013
Posts: 99
Own Kudos:
181
 [44]
Given Kudos: 21
Posts: 99
Kudos: 181
 [44]
29
Kudos
Add Kudos
15
Bookmarks
Bookmark this Post
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,438
Own Kudos:
79,375
 [38]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,438
Kudos: 79,375
 [38]
20
Kudos
Add Kudos
18
Bookmarks
Bookmark this Post
General Discussion
User avatar
yogeshsheth
Joined: 01 Oct 2006
Last visit: 19 Jul 2008
Posts: 301
Own Kudos:
76
 [13]
Posts: 301
Kudos: 76
 [13]
5
Kudos
Add Kudos
8
Bookmarks
Bookmark this Post
Let original hourly wage be x and let the no of hours worked be y
Total wage will be =x*y
After the increment the wage will be=1.25 x
Now we need to find number of hours worked so that

x*y=1.25x*z i.e z=4/5 y

%decrease = (y-4/5y)/y *100=100/5=20%.
Thus my answer is B.

Correct me if I am wrong.
User avatar
anordinaryguy
Joined: 28 May 2011
Last visit: 18 Dec 2015
Posts: 108
Own Kudos:
162
 [2]
Given Kudos: 7
Location: United States
Concentration: General Management, International Business
GMAT 1: 720 Q49 V38
GPA: 3.6
WE:Project Management (Computer Software)
GMAT 1: 720 Q49 V38
Posts: 108
Kudos: 162
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
enigma123
A part time employee whose hourly wage was increased by 25% decided to reduce the number of hours worked per week so that the employee's total weekly income would remain unchanged. By what percent should the number of hours worked be reduced?

Ans: 20%

Can anyone please tell me the approach to solve this question?

Number of Hours he works today = N
Hourly Wage today = P


Number of Hours he works today = M
Hourly wage after increase = P + 25% = P(1+25/100) = P * (5/4)

To keep the total wage constant :
N*P = M * P * (5/4)

M / N = 4/5
(N-M) / N = 1/5 (fraction by which Number of hours can be decreased while keeping total wage same)

To get the percentage , multiply both side by 100

percent of the number of hours worked be reduced ((N-M) *100/ N) = 100/5 = 20%
avatar
Tangkwa16
Joined: 04 May 2011
Last visit: 06 Nov 2011
Posts: 7
Own Kudos:
Given Kudos: 7
Posts: 7
Kudos: 1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
A = hours of work BEFORE wage increase
B= hours of work AFTER wage increase
when answering about increase or decrease, we need to make the denomenator being the old one.
Here we know that to get the same total wage, A must be 1.25 times of B;
(x is a multiple of #hours, it will get cancel out)

Decrease of hrs = (Bx-Ax)/Ax = (1-1.25)/1.25 = 0.2 = 20%
User avatar
nikhilsamuel89
Joined: 25 Sep 2010
Last visit: 30 Sep 2021
Posts: 36
Own Kudos:
53
 [1]
Given Kudos: 51
Location: France
Posts: 36
Kudos: 53
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Let initial salary be X. Then new salary is 1.25X.
Let the initial no. of hours = h1 and final no. of hours = h2;
given:
X(h1) = 1.25X(h2)
=> h1 = 1.25(h2) (cancelling X on both sides)
We need to find the percent change in no. of hours:

Formula:
Percent change = (New - Original)/Original * 100
=> (h2 - h1)/h1 * 100
Now,
We know that h1 = 1.25(h2)
=> h2/h1 = 1/1.25;
Using dividendo;
we get (h2 - h1)/h1 = (1-1.25)/1.25 ------(1)
We get our answer by multiplying (1) with 100
User avatar
Spidy001
Joined: 01 Feb 2011
Last visit: 16 Feb 2015
Posts: 298
Own Kudos:
Given Kudos: 42
Posts: 298
Kudos: 355
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hourly Wage

Initial New

$P $125P/100

X hours <X (lets say Y)

given

PX = (125P/100)Y

=> X = (125/100)Y

% decrease = ((x - y)/x )*100


= 20%
User avatar
gladvijay
Joined: 27 Feb 2011
Last visit: 08 Sep 2011
Posts: 22
Own Kudos:
9
 [3]
Given Kudos: 9
Posts: 22
Kudos: 9
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
w1 * h1 = w2 * h2

w1 * h1 = 1.25 w1 * h2 => h2 = 4 h1/ 5 = 0.8 h1 => 20% decrease
User avatar
krishp84
Joined: 16 Jan 2011
Last visit: 21 Nov 2015
Posts: 123
Own Kudos:
237
 [2]
Given Kudos: 62
Status:On...
Posts: 123
Kudos: 237
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
hahaha...If you read this question and are a consultant who is paid hourly wages....you will think :

Hey, my current hourly rate is 100 $. Now it has increased by 25%.I can reduce the time I work, because I am now earning more and want to spend time on some of my hobbies/free time :D

So how much % time can I work less !!!

100 $ per hr(1 hr) = 125$ per hr(new time in hrs) ==> new time = 100/125 hrs = 100/25.5 = 20/25 = 80/100
Old time = 1 hr

Time decrease = 1-80/100 = 20/100 or 20%

I am not putting any approach, just a practical way I would have seen this problem...
User avatar
icaniwill
Joined: 05 Oct 2011
Last visit: 29 Nov 2016
Posts: 123
Own Kudos:
93
 [5]
Given Kudos: 62
Products:
Posts: 123
Kudos: 93
 [5]
2
Kudos
Add Kudos
3
Bookmarks
Bookmark this Post
By far the quickest way to solve this problem is by using number plugging as the question is asking a percent in the end.

assume:
Employee initial salary = $100
Old hours: 20
New salary = $125
New hours: x

20 * 100 = x * 125
x = 16
Percent of reduction = 4/20 * 100 = 20%

Answer: B
User avatar
Temurkhon
Joined: 23 Jan 2013
Last visit: 06 Apr 2019
Posts: 408
Own Kudos:
325
 [3]
Given Kudos: 43
Schools: Cambridge'16
Schools: Cambridge'16
Posts: 408
Kudos: 325
 [3]
1
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
Picking works better

100- old wage
50 - old hours
100+25=125 - new wage

50*100=125x
x=40, so 50-40*100/50=20%

B
avatar
PareshGmat
Joined: 27 Dec 2012
Last visit: 10 Jul 2016
Posts: 1,531
Own Kudos:
8,270
 [3]
Given Kudos: 193
Status:The Best Or Nothing
Location: India
Concentration: General Management, Technology
WE:Information Technology (Computer Software)
Posts: 1,531
Kudos: 8,270
 [3]
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Wage ........... No. of Hrs .................. Total

10 ...................... 10 ............................ 100 (Initially)

12.5 .................... 10 .............................. 125 (After increment of 10% wage)

12.5 ...................... x .......................... 100 (Lets say no. of hrs worked = x for 100)

\(x = \frac{100}{12.5} = 8\)

Reduction percentage \(= \frac{10-8}{10} * 100 = 20%\)

Answer = B
User avatar
swanidhi
Joined: 11 Oct 2013
Last visit: 14 Jul 2023
Posts: 66
Own Kudos:
Given Kudos: 137
Concentration: Marketing, General Management
GMAT 1: 600 Q41 V31
GMAT 1: 600 Q41 V31
Posts: 66
Kudos: 340
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hours * Wage per hour = Wage

New Wage -
Hours * 1.25 * Wage per hour = 1.25 * Wage

So, New Wage = 1.25 * Old Wage
Now, forget Hours or Wage per hour. We need to decrease New Wage to make it equal to Old Wage.
So % decrease is
(New Wage - Old Wage)/New Wage = (1.25 - 1)/1.25 = 0.25/1.25 = 1/5 = 20%
avatar
Captain RoY
Joined: 18 Sep 2017
Last visit: 07 Nov 2017
Posts: 4
Own Kudos:
5
 [4]
Given Kudos: 3
Posts: 4
Kudos: 5
 [4]
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
omg!!
it's really a simple math
just follow the rule.......

reduction in consumption =[( r/100+r)*100]%
=25/125*100
=20%
so, the best answer is 20%
hope it is helpful!!!
User avatar
arvind910619
Joined: 20 Dec 2015
Last visit: 18 Oct 2024
Posts: 815
Own Kudos:
Given Kudos: 755
Status:Learning
Location: India
Concentration: Operations, Marketing
GMAT 1: 670 Q48 V36
GRE 1: Q157 V157
GPA: 3.4
WE:Engineering (Manufacturing)
Products:
GMAT 1: 670 Q48 V36
GRE 1: Q157 V157
Posts: 815
Kudos: 615
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi Let the number of hours be in 1 week x
and his hourly wage be y
then his total weekly income will be =x*y
His hourly wage increased by 25 % then his new hourly wage will be =1.25y
But he reduces his number of hours worked to maintain same total wage , therefore we have ,
Let a% be the actual decrease in y
Then
1.25axy=xy
a=1/1.25=4/5 =80% so hours are by reduced by 20%
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 21 Apr 2026
Posts: 22,276
Own Kudos:
26,526
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,276
Kudos: 26,526
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
SimaQ
A part-time employee whose hourly wage was increased by 25 percent decided to reduce the number of hours worked per week so that the employee's total weekly income would remain unchanged. By what percent should the number of hours worked be reduced?

(A) 12.5%
(B) 20%
(C) 25%
(D) 50%
(E) 75%

We can let the employee’s wage = w, the number of hours = h, and the percentage reduction = n. Thus:

wh = (1 - n/100)(w)(h)(1.25)

We can divide both sides by wh, convert 1.25 to 5/4, and re-express (1-n/100) as (100 - n)/100 to get:

1 = (100 - n)/100 x 5/4

4/5 = (100 - n)/100

400 = 5(100 - n)

80 = 100 - n

n = 20

Answer: B
User avatar
generis
User avatar
Senior SC Moderator
Joined: 22 May 2016
Last visit: 18 Jun 2022
Posts: 5,258
Own Kudos:
37,724
 [2]
Given Kudos: 9,464
Expert
Expert reply
Posts: 5,258
Kudos: 37,724
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
SimaQ
A part-time employee whose hourly wage was increased by 25 percent decided to reduce the number of hours worked per week so that the employee's total weekly income would remain unchanged. By what percent should the number of hours worked be reduced?

(A) 12.5%
(B) 20%
(C) 25%
(D) 50%
(E) 75%
30-sec approach: By what percent must hours worked decrease so that total weekly income remains unchanged?
By 1 - (fractional inverse of the percent increase)

When the original quantity is the start and end value, percent increase and percent decrease are inversely proportional. Use a fraction for the percent increase of one factor. Flip that fraction. Subtract from 1. The result is the percent by which the other factor must decrease. Thus:

\(xy = 1\)
\(x\) increases by 25% = 1.25* = \(\frac{5}{4}\)

Flip to \(\frac{4}{5}\) and subtract from 1 to yield percent by which \(y\) must decrease:

\(1 - \frac{4}{5} = \frac{1}{5}\) = 20 percent

(Or assess the flipped fraction: \(\frac{4}{5}\) = .8 = 80 percent = 20 percent decrease)

Note: if \(xy = 1\), then

\(\frac{5}{4}x *\\
\frac{4}{5}y =\\
1\)

Longer method, w/ numbers (no need!):

x = wage per hour = $20
y = # of hours worked = 10

(Wage per hour)(# of hours) = total weekly income

Total wages = $20 * 10 = $200

x, $20, increases by 25 percent:

x = \(\frac{5}{4}(20)\) = 25. We want $200. What is y?

\((25)(y)= 200\), so \(y = 8\)

By what percent did y decrease?

\(\frac{new-old}{old} =\frac{10-8}{10} =\frac{1}{5} = .20 * 100 =\) 20%

In other words, when you want the original quantity to remain the same and one factor increases by a percent, to calculate the corresponding percent decrease, finding and flipping the fraction works.

Answer B

*An increase of 25 percent =
\(1.25 =1\frac{25}{100} = 1\frac{1}{4} = \frac{5}{4}\)
User avatar
thesip2323
Joined: 08 Jul 2019
Last visit: 03 Dec 2022
Posts: 30
Own Kudos:
Given Kudos: 732
Posts: 30
Kudos: 7
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Can someone explain why my method is wrong...I'm getting nowhere close to the correct answer:

xy = 5x/4 * [(100-y)/100] .. so solve for y here.
xy = (500x-5xy)/400
400xy = 500x-5xy
405xy = 500x
y = 500/405 = 10/9 ... but obviously this is not the answer and I can't see what mistake I made.

If I use 100 = xy to start...then I can get the answer because 5x/4 just becomes 125 but if I try to just use variables throughout the equation, I mess it up so badly. Any help please!!
User avatar
ArunGour
Joined: 29 Jul 2021
Last visit: 23 Aug 2024
Posts: 16
Own Kudos:
Given Kudos: 37
Location: India
Posts: 16
Kudos: 9
Kudos
Add Kudos
Bookmarks
Bookmark this Post
yogeshsheth
Let original hourly wage be x and let the no of hours worked be y
Total wage will be =x*y
After the increment the wage will be=1.25 x
Now we need to find number of hours worked so that

x*y=1.25x*z i.e z=4/5 y

%decrease = (y-4/5y)/y *100=100/5=20%.
Thus my answer is B.

Correct me if I am wrong.


How did you get 4/5y?
x*y=1.25x*z i.e z=4/5 y here
 1   2   
Moderators:
Math Expert
109729 posts
Tuck School Moderator
853 posts