Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Nov 2007:30 AM PST
-08:30 AM PST
Learn what truly sets the UC Riverside MBA apart and how it helps in your professional growth
Nov 2211:00 AM IST
-01:00 PM IST
Do RC/MSR passages scare you? e-GMAT is conducting a masterclass to help you learn – Learn effective reading strategies Tackle difficult RC & MSR with confidence Excel in timed test environment- Nov 23
11:00 AM IST
-01:00 PM IST
Attend this free GMAT Algebra Webinar and learn how to master the most challenging Inequalities and Absolute Value problems with ease. 
Nov 2510:00 AM EST
-11:00 AM EST
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors.
13 May 2012, 08:13
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
46% (02:58) correct
54%
(03:07)
wrong
based on 1209
sessions
History
Date
Time
Result
Not Attempted Yet
A person inherited few gold coins from his father. If he put 9 coins in each bag then 7 coins are left over. However if he puts 7 coins in each bag then 3 coins are left over. What is the number of coins he inherited from his father.
(1) The number of coins lies between 50 to 120.
(2) If he put 13 coins in each bag then no coin is left over and number of coins being lesser than 200.
(1) The number of coins lies between 50 to 120.
(2) If he put 13 coins in each bag then no coin is left over and number of coins being lesser than 200.
14 May 2012, 00:28
Kudos
Bookmarks
A person inherited few gold coins from his father. If he put 9 coins in each bag then 7 coins are left over. However if he puts 7 coins in each bag then 3 coins are left over. What is the number of coins he inherited from his father.
If he puts 9 coins in each bag then 7 coins are left over --> \(c=9q+7\), so # of coins can be: 7, 16, 25, 34, 43, 52, 61, ...
If he puts 7 coins in each bag then 3 coins are left over --> \(c=7p+3\), so # of coins can be: 3, 10, 17, 24, 31, 38, 45, 52, 59, ...
General formula for \(c\) based on above two statements will be: \(c=63k+52\) (the divisor should be the least common multiple of above two divisors 9 and 7, so 63 and the remainder should be the first common integer in above two patterns, hence 52). For more about this concept see: manhattan-remainder-problem-93752.html#p721341, when-positive-integer-n-is-divided-by-5-the-remainder-is-90442.html#p722552, when-the-positive-integer-a-is-divided-by-5-and-125591.html#p1028654
\(c=63k+52\) means that # of coins can be: 52, 115, 178, 241, ...
(1) The number of coins lies between 50 to 120 --> # of coins can be 52 or 115. Not sufficient.
(2) If he put 13 coins in one bag then no coin is left over and number of coins being lesser than 200 --> # of coins is a multiple of 13 and less than 200: only 52 satisfies this condition. Sufficient.
Answer: B.
If he puts 9 coins in each bag then 7 coins are left over --> \(c=9q+7\), so # of coins can be: 7, 16, 25, 34, 43, 52, 61, ...
If he puts 7 coins in each bag then 3 coins are left over --> \(c=7p+3\), so # of coins can be: 3, 10, 17, 24, 31, 38, 45, 52, 59, ...
General formula for \(c\) based on above two statements will be: \(c=63k+52\) (the divisor should be the least common multiple of above two divisors 9 and 7, so 63 and the remainder should be the first common integer in above two patterns, hence 52). For more about this concept see: manhattan-remainder-problem-93752.html#p721341, when-positive-integer-n-is-divided-by-5-the-remainder-is-90442.html#p722552, when-the-positive-integer-a-is-divided-by-5-and-125591.html#p1028654
\(c=63k+52\) means that # of coins can be: 52, 115, 178, 241, ...
(1) The number of coins lies between 50 to 120 --> # of coins can be 52 or 115. Not sufficient.
(2) If he put 13 coins in one bag then no coin is left over and number of coins being lesser than 200 --> # of coins is a multiple of 13 and less than 200: only 52 satisfies this condition. Sufficient.
Answer: B.
General Discussion
13 May 2012, 23:32
Kudos
Bookmarks
If C = number of coins then C = 7m+3 = 9n + 7, where m and n are the number of bags used in the 7 coins per bag and 9 coins per bag case respectively.
Using statement (1), C lies between 50 and 120. However, 52 and 115 both satisfy the condition. Insufficient.
Using statement (2), C is less than 200. Only 52 satisfies all three conditions. Sufficient.
B it is.
Using statement (1), C lies between 50 and 120. However, 52 and 115 both satisfy the condition. Insufficient.
Using statement (2), C is less than 200. Only 52 satisfies all three conditions. Sufficient.
B it is.
