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A Person is 280 meters behind a bus. Then the man starts running towar

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A Person is 280 meters behind a bus. Then the man starts running towar  [#permalink]

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New post Updated on: 02 Oct 2018, 01:18
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Question Stats:

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A Person is 280 meters behind a bus. Then the man starts running towards the bus and at the same time, the bus starts moving away from the Person. If the speed of the bus is 2m/s and that of the person is 24Km/hr, In how much time will the person catch the bus?

a) 60 seconds
b) 80 seconds
c) 90 seconds
d) 120 seconds
e) None of these

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Originally posted by Afc0892 on 01 Oct 2018, 23:42.
Last edited by Afc0892 on 02 Oct 2018, 01:18, edited 1 time in total.
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Re: A Person is 280 meters behind a bus. Then the man starts running towar  [#permalink]

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New post Updated on: 02 Oct 2018, 00:46
1
Afc0892 wrote:
A Person is 280 meters behind a bus. Then the man starts running towards the bus and at the same time, the bus starts moving away from the Person. If the speed of the bus is 2m/s and that of the person is 24Km/hr, In how much time will the person catch the bus?

a) 60 minutes
b) 80 minutes
c) 90 minutes
d) 120 minutes
e) None of these


speed of the person = \(\frac{(24 *1000 )}{3600}\) =\(\frac{20}{3}\) m/s

Relative speed = \(\frac{20}{3}\) - 2 (since they are moving in the same direction) = \(\frac{14}{3}\)

time taken =\(\frac{280}{(14/3)}\) = 60 seconds

E

pretty handy if we can remember the following same as 1000/3600 stuff

1. When converting from kmph to mps multiply with \(\frac{5}{18}\)
2. When converting from mps to kmph multiply with \(\frac{18}{5}\)

Originally posted by CounterSniper on 01 Oct 2018, 23:54.
Last edited by CounterSniper on 02 Oct 2018, 00:46, edited 1 time in total.
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Re: A Person is 280 meters behind a bus. Then the man starts running towar  [#permalink]

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New post 02 Oct 2018, 00:39
2
CounterSniper wrote:
Afc0892 wrote:
A Person is 280 meters behind a bus. Then the man starts running towards the bus and at the same time, the bus starts moving away from the Person. If the speed of the bus is 2m/s and that of the person is 24Km/hr, In how much time will the person catch the bus?

a) 60 minutes
b) 80 minutes
c) 90 minutes
d) 120 minutes
e) None of these


speed of the person = \(\frac{(24 *1000 )}{3600}\) =\(\frac{20}{3}\) m/s

Relative speed = \(\frac{20}{3}\) - 2 (since they are moving in the same direction) = \(\frac{14}{3}\)

time taken =\(\frac{280}{(14/3)}\) = 60 minutes

A

pretty handy if we can remember the following same as 1000/3600 stuff

1. When converting from kmph to mps multiply with \(\frac{5}{18}\)
2. When converting from mps to kmph multiply with \(\frac{18}{5}\)


CounterSniper But shouldn't your answer be in seconds? You have used 280m / (m/s). Then the answer has to be 60sec=1min.
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Re: A Person is 280 meters behind a bus. Then the man starts running towar  [#permalink]

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New post 02 Oct 2018, 00:47
artiom01 wrote:
CounterSniper wrote:
Afc0892 wrote:
A Person is 280 meters behind a bus. Then the man starts running towards the bus and at the same time, the bus starts moving away from the Person. If the speed of the bus is 2m/s and that of the person is 24Km/hr, In how much time will the person catch the bus?

a) 60 minutes
b) 80 minutes
c) 90 minutes
d) 120 minutes
e) None of these


speed of the person = \(\frac{(24 *1000 )}{3600}\) =\(\frac{20}{3}\) m/s

Relative speed = \(\frac{20}{3}\) - 2 (since they are moving in the same direction) = \(\frac{14}{3}\)

time taken =\(\frac{280}{(14/3)}\) = 60 minutes

A

pretty handy if we can remember the following same as 1000/3600 stuff

1. When converting from kmph to mps multiply with \(\frac{5}{18}\)
2. When converting from mps to kmph multiply with \(\frac{18}{5}\)


CounterSniper But shouldn't your answer be in seconds? You have used 280m / (m/s). Then the answer has to be 60sec=1min.


Yes it should be 60 seconds
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Re: A Person is 280 meters behind a bus. Then the man starts running towar  [#permalink]

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New post 02 Oct 2018, 01:18
artiom01 wrote:
CounterSniper wrote:
Afc0892 wrote:
A Person is 280 meters behind a bus. Then the man starts running towards the bus and at the same time, the bus starts moving away from the Person. If the speed of the bus is 2m/s and that of the person is 24Km/hr, In how much time will the person catch the bus?

a) 60 minutes
b) 80 minutes
c) 90 minutes
d) 120 minutes
e) None of these


speed of the person = \(\frac{(24 *1000 )}{3600}\) =\(\frac{20}{3}\) m/s

Relative speed = \(\frac{20}{3}\) - 2 (since they are moving in the same direction) = \(\frac{14}{3}\)

time taken =\(\frac{280}{(14/3)}\) = 60 minutes

A

pretty handy if we can remember the following same as 1000/3600 stuff

1. When converting from kmph to mps multiply with \(\frac{5}{18}\)
2. When converting from mps to kmph multiply with \(\frac{18}{5}\)


CounterSniper But shouldn't your answer be in seconds? You have used 280m / (m/s). Then the answer has to be 60sec=1min.



Edited. Thank you :)
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Re: A Person is 280 meters behind a bus. Then the man starts running towar   [#permalink] 02 Oct 2018, 01:18
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A Person is 280 meters behind a bus. Then the man starts running towar

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